3 2 1 0 -1 -2 0.00086 0.00088 0.0009 Arrhenius Plot 0.00092 0.00094 0.00096 0.00098 0.001 0.00102 B. Calculate the activation energy Ea for the reaction. 1) based on the slope of the line on the graph (show your work) (calculate rise/run) 2) using 2point Arrhenius equation and experiments 1 & 2 C. What is the value of the half-life at 863°C if the initial concentration of NO₂ is 0.0550 M?

Introductory Chemistry: A Foundation
9th Edition
ISBN:9781337399425
Author:Steven S. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Donald J. DeCoste
Chapter17: Equilibrium
Section: Chapter Questions
Problem 94AP
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Discc 16 On paper please
3
2
1
0
-1
-2
0.00086
0.00088
0.0009
Arrhenius Plot
0.00092
0.00094
0.00096
0.00098
0.001
0.00102
B. Calculate the activation energy Ea for the reaction.
1) based on the slope of the line on the graph (show your work) (calculate
rise/run)
2) using 2point Arrhenius equation and experiments 1 & 2
C. What is the value of the half-life at 863°C if the initial concentration of
NO₂ is 0.0550 M?
Transcribed Image Text:3 2 1 0 -1 -2 0.00086 0.00088 0.0009 Arrhenius Plot 0.00092 0.00094 0.00096 0.00098 0.001 0.00102 B. Calculate the activation energy Ea for the reaction. 1) based on the slope of the line on the graph (show your work) (calculate rise/run) 2) using 2point Arrhenius equation and experiments 1 & 2 C. What is the value of the half-life at 863°C if the initial concentration of NO₂ is 0.0550 M?
16. At higher temperatures, the same reaction: 2 NO₂+2 NO(g) + O₂(g)
follows second order kinetics.
Using some of the experimental data shown,
Temperature
k, M-¹ S-¹
Temperature
(K)
(°C)
863
780
727
11.59
2.34
0.380
A. Sketch an Arrhenius plot with properly labeled axes.
1/T
Ink
Transcribed Image Text:16. At higher temperatures, the same reaction: 2 NO₂+2 NO(g) + O₂(g) follows second order kinetics. Using some of the experimental data shown, Temperature k, M-¹ S-¹ Temperature (K) (°C) 863 780 727 11.59 2.34 0.380 A. Sketch an Arrhenius plot with properly labeled axes. 1/T Ink
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