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3. A greenhouse has a glass dome in the shape of the paraboloid z=8-2x²-2y2 and a flat wooden floor at z = 0. Let S be the closed surface formed by the dome and the floor, oriented with outward unit normal. Suppose that the temperature in the greenhouse is given by T(x, y, z) = x²+ y²+3(z− 2)². The temperature gives rise to a heat flux density field F(x, y, z)-kVT - where k is a positive constant that depends on the insulating properties of the medium. Assume that k = 1 on the glass dome and k = 3 on the wooden floor of the greenhouse. (a) Sketch S, clearly labelling any intercepts and the direction of the normal vector. (b) Write down an expression in terms of x, y and z for the vector field F on the greenhouse. (c) By direct calculation (do not use any integral theorems), find the total heat flux F.ndS across the greenhouse in the direction of the outward unit normal.

3. A greenhouse has a glass dome in the shape of the paraboloid z=8-2x²-2y2 and a flat wooden floor at z = 0. Let S be the closed surface formed by the dome and the floor, oriented with outward unit normal. Suppose that the temperature in the greenhouse is given by T(x, y, z) = x²+ y²+3(z− 2)². The temperature gives rise to a heat flux density field F(x, y, z)-kVT - where k is a positive constant that depends on the insulating properties of the medium. Assume that k = 1 on the glass dome and k = 3 on the wooden floor of the greenhouse. (a) Sketch S, clearly labelling any intercepts and the direction of the normal vector. (b) Write down an expression in terms of x, y and z for the vector field F on the greenhouse. (c) By direct calculation (do not use any integral theorems), find the total heat flux F.ndS across the greenhouse in the direction of the outward unit normal.

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter3: Functions And Graphs
Section3.3: Lines
Problem 30E
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3. A greenhouse has a glass dome in the shape of the paraboloid z=8-2x²-2y2 and a flat wooden floor at z = 0. Let S be the closed surface formed by the dome and the floor, oriented with outward unit normal. Suppose that the temperature in the greenhouse is given by T(x, y, z) = x²+ y²+3(z − 2)². The temperature gives rise to a heat flux density field F(x, y, z) -kVT = where k is a positive constant that depends on the insulating properties of the medium. Assume that k = 1 on the glass dome and k = 3 on the wooden floor of the greenhouse. (a) Sketch S, clearly labelling any intercepts and the direction of the normal vector. (b) Write down an expression in terms of x, y and z for the vector field F on the greenhouse. (c) By direct calculation (do not use any integral theorems), find the total heat flux F.ndS across the greenhouse in the direction of the outward unit normal.
Transcribed Image Text:3. A greenhouse has a glass dome in the shape of the paraboloid z=8-2x²-2y2 and a flat wooden floor at z = 0. Let S be the closed surface formed by the dome and the floor, oriented with outward unit normal. Suppose that the temperature in the greenhouse is given by T(x, y, z) = x²+ y²+3(z − 2)². The temperature gives rise to a heat flux density field F(x, y, z) -kVT = where k is a positive constant that depends on the insulating properties of the medium. Assume that k = 1 on the glass dome and k = 3 on the wooden floor of the greenhouse. (a) Sketch S, clearly labelling any intercepts and the direction of the normal vector. (b) Write down an expression in terms of x, y and z for the vector field F on the greenhouse. (c) By direct calculation (do not use any integral theorems), find the total heat flux F.ndS across the greenhouse in the direction of the outward unit normal.
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There was an error in the question, the 'delta T' should not be bold, the equation should read-

F(x,y,z)=−k∇T

The temperature is a scalar function, with that taken into consideration, could you make any necessary changes in the working and answer?

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