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- 3) Draw the structures of the major organic product(s) for the following reactions. HI in CH₂Cl₂ 3 excess Cl₂ in H₂O H₂SO4 in H₂O (Two products) Br-Cl in THF 1) BH3 2) alkaline H₂O₂ OSO4 + HOOHAssuming nucleophilic substitution reactions will occur, which will produce racemic products? CH;CH,CH(CI)CH3 + NANH, CH3CH2CH(CI) CH3 + CH3S¯Na* CH;CH,CH(CI)CH,CH3 + NH3 O CH;CH2CH(CI) CH3 + CH3OH2. What Alkene would be used to synthesize 3-bromohexane? + HBr CH3CH2CHCH2CH2CH3 Br
- What is the predicted product of the reaction shown? O & N(CH3)2 | IV (CH3)2NH H₂SO4 1. N(CH3)2 2. H3O+ || ОН HO |||4) Fill in the appropriate starting materials, reagents or products in the following reactions. OH / AIC13 NO₂ Y CI / AICI,How many stereoisomers are formed in the reaction below? Please note: both alkenes will react under these conditions. 1. Hg(OAc)2, H2O/THF 2. NaBH4 O 2 O 16 O 3 O 8 O 4
- What product(s) is(are) formed in the following reaction Br/CH-Clz Br plus enantiomer H3C Et Br Br H and H3C Br H3C Et Et Br он ...Et plus enantiomer H3C Br2-butanol reacts with HCl in the presence of ZnCl2 at high temperature. The final product of the reaction: A has inversion of configuration B is racemic C) none of these has retention of configuration2. Explain the selectivity of the following reaction, which produces a single product despite both alkene carbons being equally substituted. H3C CF3 HBr CF3 H3C CF3 H3C Br- H3C only product -H CF3
- C12T04Q8272 Give the major product(s) of the following reaction. CrO3 он H,SO4 H. of HO, OMe HO. There is no reaction under these conditions or the correct product is not listed here.Which represents an efficient synthetic route to go from an alkane to an alkene? O elimination with NaNH2, followed by a water workup O anti-Markovnikov hydrohalogenation, followed by elimination O radical bromination, followed by elimination O hydration, followed by elimination O hydration, followed by ozonolysis of the double bondDraw the alkene that would react with the reagent given to account for the product formed. ? + + H₂O **** H₂S04 • You do not have to consider stereochemistry. • You do not have to explicitly draw H atoms. • In cases where there is more than one answer, just draw one. CH3 CH3 CHCCH3 | | OH CH3 +1