Please answer question 4 and please show me how to do it in excel. 4. A clinical trial is conducted to compare a new pain re-liever for arthritis to a placebo. Participants are randomlyassigned to receive the new medication or a placebo, andthe outcome is pain relief within 30 minutes. The data

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Description: Please answer question 4 and please show me how to do it in excel. 4. A clinical trial is conducted to compare a new pain re-liever for arthritis to a placebo. Participants are randomlyassigned to receive the new medication or a placebo, andthe outco

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Calculus For The Life Sciences

2nd Edition

ISBN:9780321964038

Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.

Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.

Chapter1: Functions

Section1.2: The Least Square Line

Problem 8E

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Please answer question 4 and please show me how to do it in excel.

4. A clinical trial is conducted to compare a new pain re-
liever for arthritis to a placebo. Participants are randomly
assigned to receive the new medication or a placebo, and
the outcome is pain relief within 30 minutes. The data

Expert Solution

Step 1

Note:

Since you have asked solution for question 4 specifically we will answer the same.

In EXCEL, there is no function or code to test the significance proportions for the summarized data. This can be done by using additional EXCEL Add-In Megastat.

The null and alternative hypotheses are given below.

$H_{0} : P_{1} - P_{2} = 0 H_{1} : P_{1} - P_{2} n o t e q u a l t o 0$

Step 2

Step-by-step procedure to obtain the test for difference in 2 proportions using MegaStat:

Go to MegaStat > Hypothesis tests > compare two independent proportions.
Enter x as 44 and n as 76 for group 1, x as 21 and n as 99 for group 2.
Enter 0 in Hypothesized difference and Select not equal in Alternative hypothesis.
Display confidence interval and select the value as 95%.
Click OK.

From the MegaStat output, the results of the test are given below:

from the above output, the z test statistic value is 4.98 and p -value is 0.0000006.

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