4. (a) Define the electromotive force and explain the physical mechanism of the electromotive force source.

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Chapter1: Units, Trigonometry. And Vectors
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4. (a) Define the electromotive force and explain the physical mechanism of the
electromotive force source.
(b) One circuit has constructed by electromotive force source which has ɛ = 5V
and inner resistivity r = 12. Two serial connected resistances which have
values of R1
1N and R2
5N placed in that circuit. Calculate the
%3D
powers dissipated in R1, R2 and r.
• Gauss's law:
qin
€0
Here E is the electric field vector, da is the surface element vector, qin is the
total charge enclosed by the Gaussian surface, €o is the electric constant. The
integral is taken over the closed Gaussian surface.
• Electric potential at point P due to charge q is given by
V = k2.
1 q
4T€0 r
where r is the distance between the point P and the charge q. k = 9 x
10°NM2/C², eo
= 8.854 × 10-12C²/(Nm²).
• The power is defined by
P = VI = I²R= V² /R
Transcribed Image Text:4. (a) Define the electromotive force and explain the physical mechanism of the electromotive force source. (b) One circuit has constructed by electromotive force source which has ɛ = 5V and inner resistivity r = 12. Two serial connected resistances which have values of R1 1N and R2 5N placed in that circuit. Calculate the %3D powers dissipated in R1, R2 and r. • Gauss's law: qin €0 Here E is the electric field vector, da is the surface element vector, qin is the total charge enclosed by the Gaussian surface, €o is the electric constant. The integral is taken over the closed Gaussian surface. • Electric potential at point P due to charge q is given by V = k2. 1 q 4T€0 r where r is the distance between the point P and the charge q. k = 9 x 10°NM2/C², eo = 8.854 × 10-12C²/(Nm²). • The power is defined by P = VI = I²R= V² /R
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