8. An object is thrown up from a height of 5 meters with an initial speed of 10 m/s. By physical principles it is found that its position at any instant of time is given by: Y(t) = 5 + 10t − 4, 9t - And its speed at any instant of time has the form: V(t) = 10 - 9.8t. Calculate: A) the time of rise, t¸, knowing that at that instant of time the velocity of the object is zero, that is, v (ts) = 0. = B) the maximum height, that is, and (ts). C) return time, tv, knowing that the position coordinate at that instant is y (tv) = 0. = D) the speed with which it reaches the ground, i.e., v (tv).

Functions and Change: A Modeling Approach to College Algebra (MindTap Course List)
6th Edition
ISBN:9781337111348
Author:Bruce Crauder, Benny Evans, Alan Noell
Publisher:Bruce Crauder, Benny Evans, Alan Noell
Chapter2: Graphical And Tabular Analysis
Section2.1: Tables And Trends
Problem 1TU: If a coffee filter is dropped, its velocity after t seconds is given by v(t)=4(10.0003t) feet per...
icon
Related questions
Question
I want a good solution and it is well graphed, I would appreciate it very much and without GPT chat.
8. An object is thrown up from a height of 5
meters with an initial speed of 10 m/s. By
physical principles it is found that its position
at any instant of time is given by:
Y(t) = 5 + 10t − 4, 9t
-
And its speed at any instant of time has the
form:
V(t) = 10 - 9.8t.
Calculate:
A) the time of rise, t¸, knowing that at that
instant of time the velocity of the object is
zero, that is, v (ts) = 0.
=
B) the maximum height, that is, and (ts).
C) return time, tv, knowing that the position
coordinate at that instant is y (tv) = 0.
=
D) the speed with which it reaches the ground,
i.e., v (tv).
Transcribed Image Text:8. An object is thrown up from a height of 5 meters with an initial speed of 10 m/s. By physical principles it is found that its position at any instant of time is given by: Y(t) = 5 + 10t − 4, 9t - And its speed at any instant of time has the form: V(t) = 10 - 9.8t. Calculate: A) the time of rise, t¸, knowing that at that instant of time the velocity of the object is zero, that is, v (ts) = 0. = B) the maximum height, that is, and (ts). C) return time, tv, knowing that the position coordinate at that instant is y (tv) = 0. = D) the speed with which it reaches the ground, i.e., v (tv).
Expert Solution
steps

Step by step

Solved in 2 steps with 6 images

Blurred answer
Recommended textbooks for you
Functions and Change: A Modeling Approach to Coll…
Functions and Change: A Modeling Approach to Coll…
Algebra
ISBN:
9781337111348
Author:
Bruce Crauder, Benny Evans, Alan Noell
Publisher:
Cengage Learning
Calculus For The Life Sciences
Calculus For The Life Sciences
Calculus
ISBN:
9780321964038
Author:
GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:
Pearson Addison Wesley,
Trigonometry (MindTap Course List)
Trigonometry (MindTap Course List)
Trigonometry
ISBN:
9781337278461
Author:
Ron Larson
Publisher:
Cengage Learning