A 1.25 m thin brass rod is bent in half to form a right-angled L, as shown in figure 1. The corner of the L is located at the origin. The rod has a mass per unit length of 450 g/m. Tc.g. Figure 1 Figure 2 Find the center of gravity (c.g.) for this geometry. Give the answer in vector notation, reg.- = mi Tc.g. = + mî a A different rod with the same mass per unit length, 450 g/m, is bent into an asymmetric Z shape as shown in figure 2. If a = 1.25 m, b = 0.455 m, and c = 0.625 m, what is the c.g. for this geometry? b + mj E mj

University Physics Volume 1
18th Edition
ISBN:9781938168277
Author:William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:William Moebs, Samuel J. Ling, Jeff Sanny
Chapter11: Angular Momentum
Section: Chapter Questions
Problem 24P: Repeat the preceding problem replacing the marble with a solid cylinder. Explain the new result.
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Macmillan Learning
A 1.25 m thin brass rod is bent in half to form a right-angled L, as shown in figure 1. The corner of the L is located at the origin.
The rod has a mass per unit length of 450 g/m.
Tc.g.
Figure 1
Figure 2
Find the center of gravity (c.g.) for this geometry. Give the answer in vector notation, Fe.g..
mî
Tc.g. =
+
mî
a
A different rod with the same mass per unit length, 450 g/m, is bent into an asymmetric Z shape as shown in figure 2. If
a = 1.25 m, b = 0.455 m, and c = 0.625 m, what is the c.g. for this geometry?
b
+
mĴ
mj
Transcribed Image Text:Macmillan Learning A 1.25 m thin brass rod is bent in half to form a right-angled L, as shown in figure 1. The corner of the L is located at the origin. The rod has a mass per unit length of 450 g/m. Tc.g. Figure 1 Figure 2 Find the center of gravity (c.g.) for this geometry. Give the answer in vector notation, Fe.g.. mî Tc.g. = + mî a A different rod with the same mass per unit length, 450 g/m, is bent into an asymmetric Z shape as shown in figure 2. If a = 1.25 m, b = 0.455 m, and c = 0.625 m, what is the c.g. for this geometry? b + mĴ mj
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