A 20-mm diameter steel rod, 250 mm long is subjected to a tensile force of 75 kN. If the Poisson’s ratio μ is 0.30, determine the lateral strain of the rod. Use E = 200 GPa. Ans; Ey= -3.581x10^-4mm/mm
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A 20-mm diameter steel rod, 250 mm long is subjected to a tensile force of 75 kN. If the Poisson’s ratio μ is 0.30, determine the lateral strain of the rod. Use E = 200 GPa.
Ans; Ey= -3.581x10^-4mm/mm
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- - 7.2-26 The strains on the surface of an experiment al device made of pure aluminum (E = 70 GPa. v = 0.33) and tested in a space shuttle were measured by means of strain gages. The gages were oriented as shown in the figure. and the measured strains were = 1100 X 106, h = 1496 X 10.6, and = 39.44 X l0_. What is the stress o in the x direction?An element of material in plain strain has the following strains: x = 0.001 and y = 0.0015. (a) Determine the strains for an element oriented at an angle = 250. (b) Find the principal strains of the element. Confirm the solution using Mohr’s circle for plane strain.An element of material in plain strain is subjected to shear strain xy = 0.0003. (a) Determine the strains for an element oriented at an angle = 30°. (b) Determine the principal strains of the clement. Confirm the solution using Mohr’s circle for plane strain.
- An element of material in plain strain is subjected to strains x = 0.0015, , y . = -0.0002, and xy = 0.0003. (a) Determine the strains for an element oriented at an angle = 20°. (b) Determine the principal strains of the element. Confirm the solution using Mohr’s circle for plane strain.The normal strain in a suspended bar of material of varying cross section due to its own weight is given by the expression yy/3E wherey= 2.2 lb/in.³ is the specific weight of the material, y = 5.0 in. is the distance from the free (i.e., bottom) end of the bar, L = 25 in. is the length of the bar, and E = 23000 ksi is a material constant. Determine, (a) the change in length of the bar due to its own weight. (b) the average normal strain over the length of the bar (c) the maximum normal strain in the bar. Answer: (a) ō = i (b) Eave = i (c) Emax = i x10-in. με μεThe normal strain in a suspended bar of material of varying cross section due to its own weight is given by the expression yy/3E where y = 3.0 lb/in.³ is the specific weight of the material, y = 6.3 in. is the distance from the free (i.e., bottom) end of the bar, L = 21 in. is the length of the bar, and E = 27000 ksi is a material constant. Determine, (a) the change in length of the bar due to its own weight. (b) the average normal strain over the length L of the bar (c) the maximum normal strain in the bar. Answer: (a) d = i (b) avg (c) Emax i x10-6 in. με με
- The normal strain in a suspended bar of material of varying cross section due to its own weight is given by the expression vy/3E where y = 2.3 lb/in.³ is the specific weight of the material, y = 0.8 in. is the distance from the free (i.e., bottom) end of the bar, L = 8 in. is the length of the bar, and E = 23000 ksi is a material constant. Determine, (a) the change in length of the bar due to its own weight. (b) the average normal strain over the length L of the bar. (c) the maximum normal strain in the bar.The normal strain in a suspended bar of material of varying cross section due to its own weight is given by the expression yy/3E where y = 2.4 lb/in.³ is the specific weight of the material, y = 1.8 in. is the distance from the free (i.e., bottom) end of the bar, L = 9 in. is the length of the bar, and E= 26000 ksi is a material constant. Determine, (a) the change in length of the bar due to its own weight. (b) the average normal strain over the length L of the bar. (c) the maximum normal strain in the bar. Calculate the change in length of the bar due to its own weight. Answer: x10-6 in.The normal strain in a suspended bar of material of varying cross section due to its own weight is given by the expression yy/3E where y = 2.9 lb/in.³ is the specific weight of the material, y = 0.5 in. is the distance from the free (i.e., bottom) end of the bar, L = 5 in. is the length of the bar, and E = 25000 ksi is a material constant. Determine, (a) the change in length of the bar due to its own weight. (b) the average normal strain over the length L of the bar. (c) the maximum normal strain in the bar. Part 1 * Your answer is incorrect. Calculate the change in length of the bar due to its own weight. Answer: d= i 2.416 eTextbook and Media x10-6 in.
- The normal strain in a suspended bar of material of varying cross section due to its own weight is given by the expression vy/3E where y = 2.4 lb/in.³ is the specific weight of the material, y = 3.8 in. is the distance from the free (i.e., bottom) end of the bar, L = 19 in. is the length of the bar, and E= 24000 ksi is a material constant. Determine, (a) the change in length of the bar due to its own weight. (b) the average normal strain over the length L of the bar. (c) the maximum normal strain in the bar. Part 1 Calculate the change in length of the bar due to its own weight. Answer: d = i x10-6 in.The normal strain in a suspended bar of material of varying cross section due to its own weight is given by the expression yy/3E where y = 2.8 lb/in.3 is the specific weight of the material, y = 2.0 in. is the distance from the free (i.e., bottom) end of the bar, L = 20 in. is the length of the bar, and E= 29000 ksi is a material constant. Determine, (a) the change in length of the bar due to its own weight. (b) the average normal strain over the length L of the bar. (c) the maximum normal strain in the bar. Part 1 Your answer is correct. Calculate the change in length of the bar due to its own weight. Answer: 6 = 6.436 eTextbook and Media Part 2 * Your answer is incorrect. Calculate the average normal strain over the length of the bar. Answer: Eavi 3.22 x10-6 in. eTextbook and Media Save for Later με Attempts: 1 of 5 used Attempts: 2 of 5 used Part 3 The parts of this question must be completed in order. This part will be available when you complete the part above. Submit AnswerThe normal strain in a suspended bar of material of varying cross section due to its own weight is given by the expression yy/3E where y = 2.8 lb/in.³ is the specific weight of the material, y = 2.0 in. is the distance from the free (i.e., bottom) end of the bar, L = 20 in. is the length of the bar, and E = 29000 ksi is a material constant. Determine, (a) the change in length of the bar due to its own weight. (b) the average normal strain over the length L of the bar. (c) the maximum normal strain in the bar. Part 1 Calculate the change in length of the bar due to its own weight. Answer: ō= i eTextbook and Media Save for Later x10-6 in. Attempts: 0 of 5 used Submit Answer Part 2 The parts of this question must be completed in order. This part will be available when you complete the part above. Part 3 The parts of this question must be completed in order. This part will be available when you complete the part above.