A 5 m-thick clay (Gs = 2.65, water content = 0.28) is overlain by a 4.50m-thick layer of sand (Gs = 2.60, e = 0.70, S = 0.85). The ground water table is located 4.50 m from the ground surface. Compute for the following: 1. At what depth would the vertical effective stress be equal to 120 kPa? 2. What is the vertical effective stress at a depth 9 m below the ground surface? 3. The depth of excavation required to reduce the effective stress at the bottom of the clay layer by 100 kPa.
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- Ground surface 2. The soil profile for a proposed construction site is shown. The groundwater table is located 2 m below the ground surface. Assume geostatic conditions and ignore any negative pore-water pressures due to capillary rise. Yt = 13.2 kN/m 2. Sand Ysat =? G, = 2.70 n= 0.5 (a) What is the effective stress (kPa) at point A? (Ans: 43 kPa) (b) What is the effective stress (kPa) at point B? (Ans: 82 kPa) (c) Ten years from now, the depth of the groundwater table will change, resulting in a new effective stress at point B of 72.6 kPa. Based on this information, how far below the ground surface will the new location of the groundwater table be? (Ans: 0 m; GWT is at the ground surface) A Clay Ysat = 19.6 kN/mA 5 m-thick clay (Gs = 2.65, water content = 0.28) is overlain by a 4.50m-thick layer of sand (Gs = 2.60, e = 0.70, S = 0.85). The ground water table is located 4.50 m from the ground surface. Compute for the following: 1. At what depth would the vertical effective stress be equal to 120 kPa? 2. What is the vertical effective stress at a depth 9 m below the ground surface? 3. The depth of excavation required to reduce the effective stress at the bottom of the clay layer by 100 kPa. Question 1: A. 1.94 Question 1: B. 3.99 Question 1: C. 6.44 Question 1: D. 8.49 Question 2: A. 168.9 Question 2: B. 44.1 Question 2: C. 120.1 Question 2: D. 124.8 Question 3: A. 1.83 Question 3: B. 7.67 Question 3: C. 3.17 Question 3: D. 6.33A 5 m-thick clay (Gs = 2.65, water content = 0.28) is overlain by a 4.50m-thick layer of sand (Gs = 2.60, e = 0.70, S = 0.85). The ground water table is located 4.50 m from the ground surface. Compute for the following: 1. At what depth would the vertical effective stress be equal to 120 kPa? 2. What is the vertical effective stress at a depth 9 m below the ground surface? 3. The depth of excavation required to reduce the effective stress at the bottom of the clay layer by 100 kPa.
- Given H1 = 8.3 m., and H2 = 4.43 m. If the ground water table rises by 2.29 meters, determine the change in effective stress (numerical value only, in kPa) at the bottom of the clay layer. Properties of dry sand: Gs = 2.59, e = 0.61. Properties of clay: Gs = 2.74, e = 0.86. Round off to two decimal places. Answer: 13.9540 Refer to the soil profile shown. Given H1 = 9.89 m., and H2 = 4.4 m. If the ground water table rises by 3.13 meters, determine the change in effective stress (numerical value only, in kPa) at the bottom of the clay layer. Properties of dry sand: Gs = 2.54, e = 0.69. Properties of clay: Gs = 2.77, e = 0.85. Round off to two decimal places.Refer to the soil profile shown. Given H1 = 8.93 m., and H2 = 5.32 m. If the ground water table rises by 2.01 meters, determine the change in effective stress (numerical value only, in kPa) at the bottom of the clay layer. Properties of dry sand: Gs = 2.56, e = 0.65. Properties of clay: Gs = 2.72, e = 0.87. Round off to two decimal places. Selected Answer: 11.95 Correct Answer: 11.95 ± 1
- Dry Sand H, Groundwater Table Clay Refer to the soil profile shown. Given H1 = 8.85 m., and H2 4.01 m If the ground water table rises by 2.19 meters, determine the change in effective stress (numerical value only, in kPa) at the bottom of the clay layer Properties of dry sand Gs = 2.51, e = 0.65 Properties of clay. Gs = 2.72, e = 0.84. Round off to two decimal places. Activate Windows Go to Settings to activate Windows. < Question 18 of 20 2 A Moving to another question will save this response. ASUS C8O CD 80 5n E R- T Y H]The saturated unit weight of a 10 m thick clay layer is 20 kN/m3. Calculate the vertical effective stress at a depth of 5 m if the groundwater level is at the surface and select the correct answer from the below: O A. Total stress = 50 kPa Porewater pressure = 48.5 kPa Effective stress = 52.1 kPa O B. Total stress = 120 kPa Porewater pressure = 40 kPa Effective stress = 60 kPa O C. Total stress = 100 kPa Porewater pressure = 49.1 kPa Effective stress = 50.1 Pa O D. Total stress 110 kPa Porewater pressure = 42.2 kPa Effective stress = 55 kPaThe water table in a deposit of uniform sand is located at 2 m below the ground level. Assuming the soil above the water table be dry and the void ratio is 0.75. The effective stress (in kN/m2, rounded off to nearest integer) at a depth of 5 m below the ground level is (upto 2 decimal places), Take G = 2.65 and Y₁ =9.81 kN/m².
- A 5m thick clay (Gs = 2.65, water content = 0.28) is overlain by a 4.5m thick layer of sand (Gs = 2.60, e = 0.70, S = 0.85). The ground water table is locate 4.5m from the ground surface. 1. at what depth would the vertical effective stress be equal to 120kpa?2. what is the vertical effective stress at a depth 9m below the ground surface? 3. what depth of excavation required to reduce the effective stress at the bottom of the clay layer by 100kpa?2. At what depth would total the vertical stress in a deep deposit of clay (e = 1.1, G;= 2.74) be 100 kPa if the water table is 1 m below the ground surface and the above the water surface a saturation degree of 90 % exists. What is the effective stress at the same depth? 3. A soil layer consists of 4 meters of sand underlying 5 meters of clay. The water table is nat- urally located at the rock bed under the soil strata but rose by 6 meters due to a recent storm. Further, capillary action is expected to develop due to the nature of the soil in ques- tion. Compute the effective stresses at the end of expected capillary action, at the end of the water table, at the interface of the clay and sand and finally at the bottom of the soil strata. Pertinent soil properties are as follows: Average S, Capil- G, D10 lary Zone Clay 2.71 0.98 0.0125 25 55% Figu Sand 2.74 0.93 N.A. N.A. N.A.Refer to the soil profile shown. Given H1 = 9.76m and H2 = 4.22 m. If the ground water table rises by 2.41 meters, determine the change in effective stress (numerical value only, in kPa) at the bottom of the clay layer. Properties of dry sand: Gs = 2.56, e =0.61. Properties of clay: Gs = 2.79, e = 0.83.