A 6.63 x 10-4 mol sample of CO₂ takes 615 seconds to effuse through a small hole. Under the same conditions, how long will it take for 6.63 x 10-4 mol of O2 to effuse? Relative atomic masses: C = 12.011; 0 = 15.999 Select one: O a. 593 s O b. 486 s O c. 617 s O d. 524 s

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Q: 2. A mixture containing only BaSO4 (FW 233.38) and CaSO4 (FW 136.14) contains one half as much Ba2+…

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A: Solutions  A)  yes B)  4.7 hours

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Q: 0.600M 1.0 0.388M 2.0 0.251M 3.0 0.163M 4.0 0.105M Use this data to answer the following questions.…

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Q: III. Calculate the change in free energy if 0.335 moles of NaI is dissolved in water at 25.0°C

A: To calculate change in free energy ( ∆G° )., We would use value of ∆H°sol and ∆S°sol of NaI .

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A: Solutions Hence option (B) is correct answer 2-Bromopropane

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Q: Calculate the solubility of silver chloride (AgCl) in g/L. Ksp = 1.6 x 10-10 MM of Ag: 107.8 g/mol;…

A: Given-> Ksp = 1.6 × 10-10 Atomic mass of Ag = 107.8 g/mole Atomic mass of Cl = 35.4 g/mole

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Q: 2HNO3(aq)+Ba(OH)2(aq)⟶2H2O(l)+Ba(NO3)2(aq)2HNO3(aq)+Ba(OH)2(aq)⟶2H2O(l)+Ba(NO3)2(aq)   A 0.100…

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Q: How many moles of N are in 0.191 g of N₂O? moles of N: mol N

A: We know that  Moles = mass ÷ molar mass

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Q: (a) FeSO4(aq) + K₂S(aq) 个

A: Complete and balance the following double-displacement chemical equation:

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A: Option D) We expect the 35p to decay by beta-minus. The daughter nucleus is 355.

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A: The answer is attached below-

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Solutions

Solutions can be considered as homogeneous mixtures which contain two or more than two chemical substances. The chemical substance which is the greater part is defined as solvent. And the chemical substance that is dissolved in a solvent is referred to as solute. Solution chemistry plays an important role in chemistry since it supports many commercial applications of solutions.