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a) An object is placed 40.0cm in front of a diverging lens with a focal length of 19.2 cm. Please provide your answers in units of cm if necessary.  Find the image distance. I answered this part and I got -13 as an answer.   But i can't solve this second part:   b) Suppose the object is brought to a distance of 11.7 cm in front of the lens. Where is the image now with respect to its previous location? (Note: Ensure the sign convention you use is consistent by treating all image distances on the object side of the lens as negative.) c)How has the height of the image changed if the object is 80.7 cm tall?   plz help me answer it. thanks

a) An object is placed 40.0cm in front of a diverging lens with a focal length of 19.2 cm. Please provide your answers in units of cm if necessary.  Find the image distance. I answered this part and I got -13 as an answer.   But i can't solve this second part:   b) Suppose the object is brought to a distance of 11.7 cm in front of the lens. Where is the image now with respect to its previous location? (Note: Ensure the sign convention you use is consistent by treating all image distances on the object side of the lens as negative.) c)How has the height of the image changed if the object is 80.7 cm tall?   plz help me answer it. thanks

University Physics Volume 3
University Physics Volume 3
17th Edition
ISBN:9781938168185
Author:William Moebs, Jeff Sanny
Publisher:William Moebs, Jeff Sanny
Chapter2: Geometric Optics And Image Formation
Section: Chapter Questions
Problem 69P: People who do very detailed work close up, such as jewelers, often can see objects clearly at much...
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a) An object is placed 40.0cm in front of a diverging lens with a focal length of 19.2 cm. Please provide your answers in units of cm if necessary. 
Find the image distance. I answered this part and I got -13 as an answer.
 
But i can't solve this second part:
 
b) Suppose the object is brought to a distance of 11.7 cm in front of the lens. Where is the image now with respect to its previous location? (Note: Ensure the sign convention you use is consistent by treating all image distances on the object side of the lens as negative.)
c)How has the height of the image changed if the object is 80.7 cm tall?
 
plz help me answer it. thanks
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