Constants | Periodic TableA calorimeter is an insulated device in which achemical reaction is contained. By measuring thetemperature change, AT, we can calculate theheat released or absorbed during the reaction usingthe following equation:Part Aq= specific heat x mass x ATA calorimeter contains 30.0 mL of water at 14.0 °C. When 1.70 g of X (a substanice with a molar mass of76.0 g/mol) is added, it dissolves via the reactionOr, if the calorimeter has a predetermined heatcapacity, C, the equation becomesX(s) + H20(1)-X(aq)q= C x ATand the temperature of the solution increases to 30.0 CAt constant pressure, the enthalpy change for thereaction, AH, is equal to the heat, gp; that is,Calculate the enthalpy change, AH, for this reaction per male of X.Assume that the specific heat of the resulting solution is equal to that of water [4.18 J/(g. C)], that densityof water is 1.00 g/mL, and that no heat is lost to the calorimeter itself, nor to the surroundings.AH = 9pExpress the change in enthalpy in kilojoules per mole to three significant figures.but it is usually expressed per mole of reactant andwith a sign opposite to that of g for thesurroundings. The total internal energy change,AE (sometimes referred to as AU), is the sum ofheat, q, and work done, ur• View Available Hint(s)ανο ΑΣφAE = q+ wkJ/molHowever, at constant volume (as with a bombcalorimeter) w = 0 and so AE= q.AH =SubmitPearsonCopyright © 2021 Pearson Education Inc. All rights reserved. Terms of Use | Privacy Policy | Permissions | Contact Us I9 1:37 ne- AP Student.O Elk Grove Unified -O My Profile-ZoomA Results of the chec.My Citationlist 9/2P Pearson Sign InO College BoadConstants | Periodic TableA calorimeter is an insulated device in which achemical reaction is contained. By measuring thetemperature change, AT, we can calculate theheat released or absorbed during the reaction usingthe following equation:Consider the reactionCn HosOu(s) + 1202(g) -→12CO2(x) + 11H2O(1)in which 10.0 g of sucrose, Ci2 H2m011. was burned in a bomb calorimeter with a heat capacity of 7.50kJ/C. The temperature increase inside the calorimeter was found to be 22.0PC Calculate the change ininternal energy. AE, for this reaction per mole of sucroseq= specific heat x mass x ATOr, if the calorimeter has a predetermined heatcapacity, C, the equation becomesExpress the change in internal energy in kilojoules per mole to three significant figures.q=C x AT• View Available Hint(s)At constant pressure, the enthalpy change for thereaction, AH, is equal to the heat, qp, that is,AH = 9,ΔΕ-kJ/molbut it is usually expressed per mole of reactant andwith a sign opposite to that of q for thesurroundings. The total internal energy change,AE (sometimes referred to as AU), is the sum ofheat, q. and work done, w:SubmitPrevious AnswersAE =q+ wX Incorrect; Try Again; 28 attempts remainingHowever, at constant volume (as with a bombcalorimeter) w=0 and so AE = q.Next Provide FeedbackP PearsonCopyright © 2021 Pearson Education Inc. All rights reserved. | Terms of Use Privacy Policy Permisslons Contact Us |PA 1:37

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Constants | Periodic TableA calorimeter is an insulated device in which achemical reaction is contained. By measuring thetemperature change, AT, we can calculate theheat released or absorbed during the reaction usingthe following equation:Part Aq= specific heat x mass x ATA calorimeter contains 30.0 mL of water at 14.0 °C. When 1.70 g of X (a substanice with a molar mass of76.0 g/mol) is added, it dissolves via the reactionOr, if the calorimeter has a predetermined heatcapacity, C, the equation becomesX(s) + H20(1)-X(aq)q= C x ATand the temperature of the solution increases to 30.0 CAt constant pressure, the enthalpy change for thereaction, AH, is equal to the heat, gp; that is,Calculate the enthalpy change, AH, for this reaction per male of X.Assume that the specific heat of the resulting solution is equal to that of water [4.18 J/(g. C)], that densityof water is 1.00 g/mL, and that no heat is lost to the calorimeter itself, nor to the surroundings.AH = 9pExpress the change in enthalpy in kilojoules per mole to three significant figures.but it is usually expressed per mole of reactant andwith a sign opposite to that of g for thesurroundings. The total internal energy change,AE (sometimes referred to as AU), is the sum ofheat, q, and work done, ur• View Available Hint(s)ανο ΑΣφAE = q+ wkJ/molHowever, at constant volume (as with a bombcalorimeter) w = 0 and so AE= q.AH =SubmitPearsonCopyright © 2021 Pearson Education Inc. All rights reserved. Terms of Use | Privacy Policy | Permissions | Contact Us I9 1:37 ne- AP Student.O Elk Grove Unified -O My Profile-ZoomA Results of the chec.My Citationlist 9/2P Pearson Sign InO College BoadConstants | Periodic TableA calorimeter is an insulated device in which achemical reaction is contained. By measuring thetemperature change, AT, we can calculate theheat released or absorbed during the reaction usingthe following equation:Consider the reactionCn HosOu(s) + 1202(g) -→12CO2(x) + 11H2O(1)in which 10.0 g of sucrose, Ci2 H2m011. was burned in a bomb calorimeter with a heat capacity of 7.50kJ/C. The temperature increase inside the calorimeter was found to be 22.0PC Calculate the change ininternal energy. AE, for this reaction per mole of sucroseq= specific heat x mass x ATOr, if the calorimeter has a predetermined heatcapacity, C, the equation becomesExpress the change in internal energy in kilojoules per mole to three significant figures.q=C x AT• View Available Hint(s)At constant pressure, the enthalpy change for thereaction, AH, is equal to the heat, qp, that is,AH = 9,ΔΕ-kJ/molbut it is usually expressed per mole of reactant andwith a sign opposite to that of q for thesurroundings. The total internal energy change,AE (sometimes referred to as AU), is the sum ofheat, q. and work done, w:SubmitPrevious AnswersAE =q+ wX Incorrect; Try Again; 28 attempts remainingHowever, at constant volume (as with a bombcalorimeter) w=0 and so AE = q.Next >Provide FeedbackP PearsonCopyright © 2021 Pearson Education Inc. All rights reserved. | Terms of Use Privacy Policy Permisslons Contact Us |PA 1:37

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