. A current-carryingwire is oriented along the x axis. It passesthrough a region 0.164 m long in whichthere is a magnetic field of 1.89 T in the +zdirection. The wire experiences a force of23 N in the +y direction as shown in thefigure.F1. ) The current can be calculatedusing the formula number (refer to formulasheet)) The magnetic field vector2."acting on the wire can be expressed as:B =3.(.t) The magnitude of the electriccurrent can be calculated using:(0.164)(23)x(1.89)(23)(1.89)x(0.164)(1.89)(23)x(0.164)4. (9 The magnitude of the currentis equal to: /=5. (. The direction of the currentflow in the wire will be pointing to:OThe rightOUpwardOThe leftODownward6.If the current direction isopposite to the calculated one, themagnetic force direction acting on thewire will be pointing to:ODownwardOThe leftOThe rightOUpward

Answered: Image /qna-images/answer/15aa17ed-1c3d-4f5c-8723-81c1ea2b9f2e.jpg

A current-carrying wire is oriented along the x axis. It passes through a region 0.164 m long in which there is a magnetic field of 1.89 T in the +z direction. The wire experiences a force of 23 N in the +y direction as shown in the figure. F ) The current can be calculated using the formula number (refer to formula sheet) 2.". acting on the wire can be expressed as: -) The magnetic field vector 3. (t) The magnitude of the electric current can be calculated using: (0.164) (23)x(1.89) (23) (1.89)x(0.164) (1.89) (23)x(0.164) 4. ( The magnitude of the current is equal to: /= The direction of the current 5. ( flow in the wire will be pointing to: OThe right OUpward OThe left ODownward 6. If the current direction is opposite to the calculated one, the magnetic force direction acting on the wire will be pointing to: ODownward OThe left OThe right OUpward OO O

A current-carrying wire is oriented along the x axis. It passes through a region 0.164 m long in which there is a magnetic field of 1.89 T in the +z direction. The wire experiences a force of 23 N in the +y direction as shown in the figure. F ) The current can be calculated using the formula number (refer to formula sheet) 2.". acting on the wire can be expressed as: -) The magnetic field vector 3. (t) The magnitude of the electric current can be calculated using: (0.164) (23)x(1.89) (23) (1.89)x(0.164) (1.89) (23)x(0.164) 4. ( The magnitude of the current is equal to: /= The direction of the current 5. ( flow in the wire will be pointing to: OThe right OUpward OThe left ODownward 6. If the current direction is opposite to the calculated one, the magnetic force direction acting on the wire will be pointing to: ODownward OThe left OThe right OUpward OO O

Glencoe Physics: Principles and Problems, Student Edition

1st Edition

ISBN:9780078807213

Author:Paul W. Zitzewitz

Publisher:Paul W. Zitzewitz

Chapter24: Magnetic Fields

Section: Chapter Questions

Problem 103A

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Similar questions

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