2 (a) In the following reaction scheme, draw the structures of the missing intermediates 5-8 andthe product 9.PhH₂NCOOHMeMeO MeDCC, DMAPCH₂Cl₂MeMe7H₂NNH₂NaBH₁F₂CCOOHCH₂Cl₂(b) Using the tripeptide below, illustrate the structure as it appears in aqueous solution at theisoelectric point and explain what this term means.Under what conditions will the net charge of the tripeptide in solution become positive, andunder what conditions will it become negative?OHMeHN-Me20%piperidineCH₂Cl₂LOH

Kindly repost b seperately. Thanks

(a) In the following reaction scheme, draw the structures of the missing intermediates 5-8 and the product 9. Ph H₂N i COOH Me Me O Me DCC, DMAP CH₂Cl₂ Me Me 7 NH₂ NaBH₁ F₂CCOOH CH₂Cl₂ 20% piperidine CH₂Cl₂

(a) In the following reaction scheme, draw the structures of the missing intermediates 5-8 and the product 9. Ph H₂N i COOH Me Me O Me DCC, DMAP CH₂Cl₂ Me Me 7 NH₂ NaBH₁ F₂CCOOH CH₂Cl₂ 20% piperidine CH₂Cl₂

Organic Chemistry

8th Edition

ISBN:9781305580350

Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote

Publisher:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote

Chapter11: Ethers, Epoxides, And Sulfides

Section: Chapter Questions

Problem 11.37P: Following are the steps in the industrial synthesis of glycerin. Provide structures for all...

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Concept explainers

Sulfur Functional Groups

Many organic molecules contain sulfur functional groups and have their own importance in chemistry as well as biology. Some of the organic molecules which contain sulfur functional groups and the corresponding sulfur functionality is given below:

Question

(a) In the following reaction scheme, draw the structures of the missing intermediates 5-8 and
the product 9.
Ph
H₂N
COOH
Me
Me
O Me
DCC, DMAP
CH₂Cl₂
Me
Me
7
H₂N
NH₂
NaBH₁
F₂CCOOH
CH₂Cl₂
(b) Using the tripeptide below, illustrate the structure as it appears in aqueous solution at the
isoelectric point and explain what this term means.
Under what conditions will the net charge of the tripeptide in solution become positive, and
under what conditions will it become negative?
OH
Me
HN-
Me
20%
piperidine
CH₂Cl₂
LOH

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