A river water sample (250 mL) is filtered and 0.032 g of solid is collected on the filter paper. Determine the total solids in the river water sample, in ppm. Density of water sample: 1.01 g/mL O A 31.7 ppm O B. 3.17 ppm O C.317 ppm O D 3170 ppm
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- A (aq) + ...B(aq) C(s) + D (aq) ... .. Experimental | Volume of B/ mL Mass of Run precipitate/g 1 1.2 5.40 2 1.4 7.24 1.6 9.02 4 1.8 9.90 2.0 10.86 6. 2.2 10.90 7 2.4 10.88 8 2.6 10.84 9. 2.8 10.86 A series of experiment was performed to determine the mole ratio of a given reaction. 1 mL of 1 Molar A added to nine beakers, then the increasing amount of 1 Molar B added to these beakers. Volume of B and mass of precipitate of C are given in the table below. Find the mole ratios through plotting a graph.1. Molarity of the NaOH solution 0.238 mol/L Trial 1 Trial 2 Trial 2. Volume of H;PO4 added to flask 22.0 mL 22.0 mL 22.0 mL 3. Initial NaOH volume _0.25_ mL _0.75_ mL 0.55 mL 4. Final NaOH volume 17.60_ mL 18.20_ mL _17.90_ mL 5. NAOH volume used for titration to reach green end point mL mL mL 6. NaOH volume used for titration 7. Moles of NaOH used for titration mol mel mel 8. Moles of H;PO4 that reacted mol mel mol 9. Volume of H;PO4 added to flask L 10. Molarity of H3PO4 mol/L mol/L mol/LB. Weight of Na2SO4 Sample 0.3512 g C. Total Vol. of Precipitant (BaCl2) used WITH 1M BaCl2 PLEASE FIND THE calculated volume of BaCl2 precipitant will be calculated using this formula: NVBaCl2 = (weight of sample)(1000)(EW) V(ml)BaCl2 = (weight sample)(1000)N(EW).
- Part A) A 10.0 mL sample of 0.250 mol/L NiF2(aq) is mixed with 20.0 mL of 0.0900 mol/L NaOH(aq) and then diluted to a final volume of 100. mL.Calculate the concentration of Ni2+ ions in the 100 mL mixture before the reaction starts. Express your answer to three significant figures.ksp: 5.48e-16o/index.html?deploymentld%=55750828934189288909969212&eiSBN=9781305657571&snapshotld%32199898&id%3... ☆ IDTAP Q Search this cou Use the References to access important values if needed for this question. The concentration of H3ASO3 in a solution is determined by titration with a 0.1945 M Ce+ solution. The balanced net ionic equation for the reaction is: 2Ce*(aq) + H3ASO3(aq) + 5H2O(1) 2Ce*(aq) + H3ASO4(aq) + 2H3O*(aq) (a) If 19.83 mL of the 0.1945 M Ce** solution are needed to react completely with 30.00 mL of the H3ASO3 solution, what is the concentration of the H3ASO3 solution? M (b) Which of the two solutions was in the buret during the titration? (c) Suppose at the end of the titration, the solution containing the Ce³* ion is transferred to a volumetric flask and diluted to 300. mL. What is the concentration of Ce3+In the diluted solution? Submit Answer 5 question attempts remainingWhat TWO things could be done to increase the solubility of a specific gas in solution? esc lock Edit Format Table 12pt v Paragraph Р !! 1 Q A 2 BIU * W S 3 Al E BV T² v 4 R % 5 D F T Ev Ev A 6 G 7 H To 188 O wo * 8
- 1.0 M H KOAC in 100 ml. Ans. 4.53. at the ec 8. 50 ml 0.1 M NH, is mixed with 100 ml 0.1 M HCI. What is the pi df the resulting mixture? 28. Sel volume Ans. 1.48. 9. Repeat problem 8, hut10. A 0.514 gram sample of NazCO, (106.0 g/mol) was dissolved in distilled water in a 100.0 mi volumetric flask. The molar concentration of Na,CO, in solution is: 0.0485 M 0.0370 M b. 0.4849 M 0.0340 M 0.0330 M d. е.marks Profiles Tab Window Help My Ho a on x C|Cheg signment/takeCovalent Activity.do?locator=assignment-take z 5.pdf V Submit Answer S Paraph Solubility of Ionic Compounds Classify each of the compounds as soluble or not soluble: soluble silver acetate soluble sodium nitrate not soluble chromium(II) sulfate OCT 12 W Math 122 Quiz 5.docx atv A very 9 Retry Entire Group 9 more group attempts remaining Hey D • Micros all Use the References to access important values if needed for this quest PA F22-Chem-103x....pdf MogRook Air A One S Untitle - 73 S Fel-F22-Chem-1....pdf 0 14 Gramn P Aa C
- Standardization of NaOH Trial 1 Trial 2 Trial 3 Trial 4 Trial 5 D. 785 O.l690g 0. 8239 Mass of KHP Final buret 16.30mL: 14.05ML 17.10ML reading Initial buret 0,00mL 0.0vmL O.comL reading Volume of NaOH Calculate the molarity of the NaOH for each trial: Trial 1 Trial 2 Trial 3 Trial 4 Trial 5 Calculated Molarity Average Molarity MB. Molar Concentration of an Acid Solution Acid type, HA or H,A: HA Unknown No. Balanced equation for neutralization of acid with NaOH. NaOH + HCI = NaCI + Sample 1 Sample 2 Sample 3 1. Volume of acid solution (mL) 25.0 25.0 25.0 2. Buret reading of NaOH, initial (mL) 0.00 0.00 0.00 3. Buret reading of NaOH, final (mL) 26.3 26.0 26.8 26.3 26.0 0.148 4. Volume of NaOH dispensed (mL) 26.8 5. Molar concentration of NAOH (mol/L), Part A 6. Moles of NaOH dispensed (mol) 7. Molar concentration of acid solution (mol/L) 8. Average molar concentration of acid solution (mol/L) Data Analysis, B 9. Standard deviation of molar concentration Data Analysis, C 10. Relative standard deviation of molar concentration (%RSD) Data Analysis, DA solution of Na,SO, in water is saturated at 50°C. When a saturated solution of Na,SO, is cooled, crystals of Na,SO4-10H2O separate from the solution Temperature, °C Solubility of Na,SO, g/100g water 49 50 46.7 10 9 If 1000 kg of this solution is cooled to 10°C, the percentage yield obtained is nearly а. 91 b. 90 с. 100 d. 80