A snake species that has migrated from the mainland to a small island eats banana slugs instead of lizards and mice, its usual diet. Which statement best explains this change in beha O The genotype that affects food choice is not isolated to a single phenotype. O Instinctual food choice by snakes is not related to genotypic flexibility. O Diet is exclusively controlled by snake genetics, not by nature. O Gene expression for mainland snakes is rigid and confined to one phenotype.

A snake species that has migrated from the mainland to a small island eats banana slugs instead of lizards and mice, its usual diet. Which statement best explains this change in beha O The genotype that affects food choice is not isolated to a single phenotype. O Instinctual food choice by snakes is not related to genotypic flexibility. O Diet is exclusively controlled by snake genetics, not by nature. O Gene expression for mainland snakes is rigid and confined to one phenotype.

Biology: The Unity and Diversity of Life (MindTap Course List)

14th Edition

ISBN:9781305073951

Author:Cecie Starr, Ralph Taggart, Christine Evers, Lisa Starr

Publisher:Cecie Starr, Ralph Taggart, Christine Evers, Lisa Starr

Chapter26: Human Evolution

Section: Chapter Questions

Problem 1DAA: Neanderthal Hair Color The MC1R gene regulates pigmentation in humans (Sections 14.1 and 15.1...

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How will this mutation affect descendants of this puppy? O The mutation will cause a genotypic change in this puppy but its descendants will not inherit this mutation. The mutation will not cause a genotypic change in the puppy and its descendants, but will cause a phenotypic change O The mutation will cause a genotypic and phenotypic change in the puppy, but the descendants are not affected by this mutation. The mutation will cause a genotypic change in the puppy but will not cause a phenotypic change in the puppy and its descendants.
In the fish Species a, the expression of different combinations of four Hox genes results in structural differences in tissues and organs along the anterior-posterior axis. Figure 3 shows the expression pattern of four genes, i.e. Genes 1 – 4, and the tissue produced along the embryonic anterior - posterior plane of fish Species a wild type. The influence of Hox genes on the formation of specific types of tissue can be determined by introducing gain-of-function and loss-of-function mutations in specific Hox genes. Looking at Figure 3, predict what would happen to each one of the four types of tissues, if the expression of gene 3 was expanded anteriorly by a gain-of-function mutation so that the pattern of gene 3 expression would be the same as that of gene 2.
Hi, would you plaase answer this question? In a study conducted by an undergraduate student, the obtained data showed that approximately 75% of the European Northern human population demonstrate the expression of a phenotype directly associated with the homozygous dominant genotype, while 25% display the mutant phenotype despite their genotypes being homozygous dominant. Using your knowledge propose two hypotheses for this observation.
Opsin proteins detect light in photoreceptor cells of theeye and are required for color vision. The nocturnal owlmonkey, the nocturnal bush baby, and the subterraneanblind mole rat have different mutations in an opsin genethat render it nonfunctional. Explain why all three species can tolerate mutations in this gene that operates inmost other mammals.
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What phenotypes do you think a homozygous tra1hsn animal with a gain of function mutation in the Egl1 would have.
imagine that you finally solved the mystery of the color pattern of zebras. One gene defines the color of the fur, with two alleles for two colors: black (B) and white (b). Both alleles are co-dominant. Another gene regulates the expression of the color through epistasis. You name the two alleles for this regulator gene G and g. The dominant allele G is necessary for the fur color (white is considered a color) to be produced. The recessive g allele does not allow fur color expression. Zebra with no fur color expression appear green. You breed two double heterozygous zebras. A)What do these double heterozygotes look like?______________________ B) Fill the Punnett square and provide the predicted proportion of zebras of different colors from that cross.... The colors obtained are the following (include expected ratio or percentage): C)Naturally, there are no green zebras. Propose a genetic explanation for this lack of green zebras? Answer:
if you replaced the hox genes that are normally expressed in a dolphin fin with the hox genes that are normally expressed in a cat's paw, you would get a dolphin with kitty cat paws. ( True or false)
The ABO blood groups in humans are expressed as the IA,IB and i alleles. The IAallele encodes the A blood group antigen, IB encodes B, and i encodes O. Both A and B are dominant to 0. If a heterozygous blood type A parent (IAi) and a heterozygous blood type B parent (IBi) mate, one quarter of their offspring are expected to have the AB blood type IAIBin which both arnigens are expressed equally. Therefore, ABO blood groups are an example of: a. multiple alleles and incomplete dominance b. codominance and incomplete dominance c. incomplete dominance only d. multiple alleles and codominance
The L gene in cats controls if they like to sit on your laptop (L) or on the book you are reading (I). L is dominant to I. The F gene controls how much fur cats shed. FF cats shed a lot, Ff cats some, and ff cats shed a little. The C gene controls how sharp their claws are: C is sharp, which is dominant to c. But it is a bit more complicated... Because the R gene controls how well they can retract their claws. rr cats cannot retract their claws, and thus, they are always touching the ground and are never sharp. Only RR or Rr cats have a possibility of sharp claws. The A gene is useful when cats are angry. AA cats growl. aa cats hiss. Aa cats growl and hiss. All of these genes are unlinked. These cats mate: Dad: LI Ff Cc Rr Aa Mom: II Ff Cc rr aa a) Which gene acts co-dominantly? b) Which gene acts partially/incompletely dominantly? c) How many types of gametes can each parent make? Show work. d) LIST all the gametes the mom cat can make. What fraction of the kittens (SHOW WORK for EACH…
O Mutation-selection balance Suppose that one allele A₁ mutates to another allele A2 at some rate, μ. Suppose as well that A₁ is dominant over A2 such that A₁A1 and A₁A2 both have the same fitness, but that individuals that are homozygous recessive (A2A2) for the mutant allele A2 are less fit than the dominant genotype by some amount s, the selection coefficient. In this case, A2 mutant alleles come into the population at rate µ, and are removed from the population only when the show up in homozygous genotypes. The gory mathematical proof can be found in Box 7.8, which tells us that: O ■ Example: Suppose A₁ mutates to A2 at rate 0.005, but A₂A2 homozygous recessives are 50% less fit (s = 0.5) than either A₁A1 or A₁A2. What are the expected equilibrial abundances of A₁ and A2? μ = 0.005 S = 0.5 p* = 1-sqrt(µ/s) = 1-sqrt(0.005/0.5) = 0.9 = sqrt(µ/s) = sqrt(0.005/0.5) = 0.1 ● * p = = 1-sqrt(µ/s) q* = sqrt(μ/s) ● Question: Suppose A₁ mutates to A2 at rate 0.01, but A₂A2 homozygous…
Three modes of dosage compensation exist in nature. a. Briefly, describe the three different strategies. b. Which of these occurs in mammals? c. Describe why patches of orange and black occur in calico cats rather than a random mix of orange and black hairs. Relate this to the dosage compensation strategy in mammals.