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A solid uniform ball with mass m and diameter d is supported against a vertical frictionless wall by a thin massless wire of length L. a) Find the tension in the wire. a) Let us first derive the expression for the tension. By Newton's First Law ΣF = the components of force that makes this so is ΣF = T - = 0 Simplifying this results to T = g/(ϕ) Analyzing the figure above, we arrive at (ϕ) = sqrt( 2 + ) / ( / + ) By substitution, we arrive at the following: T = ( + 2 ) g / ( sqrt ( 2 + ) ) If the ball has a mass of 45 kg and diameter 32 cm, while the wire has a length of 30 cm. The tension is equal to T = 0.370 N

A solid uniform ball with mass m and diameter d is supported against a vertical frictionless wall by a thin massless wire of length L. a) Find the tension in the wire. a) Let us first derive the expression for the tension. By Newton's First Law ΣF = the components of force that makes this so is ΣF = T - = 0 Simplifying this results to T = g/(ϕ) Analyzing the figure above, we arrive at (ϕ) = sqrt( 2 + ) / ( / + ) By substitution, we arrive at the following: T = ( + 2 ) g / ( sqrt ( 2 + ) ) If the ball has a mass of 45 kg and diameter 32 cm, while the wire has a length of 30 cm. The tension is equal to T = 0.370 N

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A solid uniform ball with mass m and diameter d is supported against a vertical frictionless wall by a thin massless wire of length L. a) Find the tension in the wire.

 

a)

Let us first derive the expression for the tension.

By Newton's First Law

ΣF = 

the components of force that makes this so is

ΣF = T -  = 0

Simplifying this results to

T = g/(ϕ)

Analyzing the figure above, we arrive at

(ϕ) = sqrt( 2 +  ) / ( / +  )

By substitution, we arrive at the following:

T =  (  + 2 ) g / (  sqrt ( 2 +  ) )

If the ball has a mass of 45 kg and diameter 32 cm, while the wire has a length of 30 cm. The tension is equal to

T = 0.370 N

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