staggered ction is sh force that the plate could carry. Assume A36 steel (Ey = 248 MPa, Fu provisions. For Plate: t = 12 mm, width = 350 mm For Rivet: Diameter = 20 mm
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- STAGGERED CONNECTIONS: A PLATE WITH WIDTH OF 400 mm AND THICKNESS OF 12 mm IS TO BE CONNECTED TO A PLATE OF THE SAME WIDTH AND THICKNESS BY 34 mm DIAMETER BOLTS, AS SHOWN IN THE FIGURE. THE HOLES ARE 2 mm LARGER THAN THE BOLT DIAMETER. THE PLATE IS A36 STEEL WITH YIELD STRENGTH Fy = 248 MPa. ASSUME ALLOWABLE TENSILE STRESS ON NET AREA IS 0.60Fy. IT IS REQUIRED TO DETERMINE THE VALUE OF b SUCH THAT THE NET WIDTH ALONG BOLTS 1-2-3-4 IS EQUAL TO THE NET WIDTH ALONG BOLTS 1-2-4. a. CALCULATE THE VALUE OF b IN MILLIMETERS. b. CALCULATE THE VALUE OF THE NET AREA FOR TENSION IN PLATES IN SQUARE MILLIMETERS. c. CALCULATE THE VALUE OF P SO THAT THE ALLOWABLE TENSILE STRESS ON NET AREA WILL NOT BE EXCEEDED.A 15" x 3/8" bar of A572 Gr. 50 steel is used as a tension member. It is connected to a gusset plate with 7/8-in diameter bolts as shown in the figure. Use s = 2.0 and g = 3.0.a) Determine the design tensile strength of the section based on yielding of the gross area.b) Determine the critical net area of the connection shown.Bolted and Riveted Connections From the bolted connection shown, the diameter of bolts is 18mm0 with the hole diameter equal to 3mm bigger than the bolt, the angular section is 100 x 75 x 8 mm, with an area of 1340 mm2. Thickness of the gusset plate is 9mm. The gusset plate and angle arc A36 steel with Fy = 250 MPa and Fu = 400 MPa. Determine the tensile capacity of the connection based on gross area. Determine the tensile capacity of the connection based on effective net area using a reduction factor of 0.85. Determine the tensile capacity of the connection based on gross area.
- A staggered connection is shown in the figure. Using LRFD & ASD, determine the maximum tensile force that the plate could carry. Assume A36 steel (Fy = 248 MPa, Fu = 400MPa). Use NSCP 2015 provisions. For Plate: t = 12 mm, width = 350 mm For Rivet: Diameter = 20 mm 70 100 P 70 80 70Considering the following steel connection. The plates in Pink are 9mm steel plates. The middle plate (Yellow) is 18mm thick. The width of the plate is 100mm. The maximum allowable tension stresses on any of the plates is 100Mpa in Gross Area Yielding and 150 Mpa for Net Area or Tension Rupture. The bolts used are 8mm in diameter, the holes are 10mm in diameter, no need to add 1.6mm. The bolts allow a maximum of 280 Mpa of shear. Determine the maximum allowable "P" of the connection in kN.The connection shown is subjected to a tensile force of P = 100 kN. The allowable shear stress for the bolts is 100 MPa. Assume each bolt supports an equal portion of the load. Determine the required diameter of the bolts. a. 20.6 mm b. 25.2 mm c.35.7 mm d.17.8 mm choose letter of correct answer
- Design a welded connection for an MC9x23.9 of A572 Grade 50 steel connected to a 3/8-inch-thick gusset plate (Figure 6). The gusset plate is A36 steel. Show your results on a sketch, complete with dimensions. = 3/8" Figure 6 D = 48 k L = 120 k MC9 x 23.9 a. Use LRFD. b. Use ASD.A bolted connection shown consists of two plates 300mm x12mm connected by 4 - 22 mm diameter bolts. Edge distances = 75mm dhole for tensile and rupture = db + 3 mm dhole for bearing strength for Lc = db + 1.5 mm Fy = 248 Mpa Fu = 400 Mpa Fn = 330 Mpa Use LRFD design method. Determine the design strength due to the gross yielding of plates. (kN)10 mm 20 mm The assembly above is comprised of a 10mm-diameter steel bolt, and a 20mm-diameter, 2mm-thick bronze sleeve. The bolt and sleeve are rigidly connected at each end by a washer. Assume the following properties: Epolt = 29000 ksi &bolt = 6.6-106 1°F Vbolt = 0.35 Member BC is made of bronze with the following properties: Esleeve = 15000 ksi Xsleeve =9.80-106 /°F Vsleeve = 0.35 If the assembly is heated up, which of the following statements best describes how the sleeve will be affected? The sleeve will try to expand longitudinally, but will be restricted by the bolt (because the bolt has a lower coefficient of thermal expansion). The sleeve will go into tension and the bolt will go into compression. O The sleeve will try to expand longitudinally, but will be restricted by the bolt (because the bolt has a lower coefficient of thermal expansion). Both members will go into tension. The sleeve will try to expand longitudinally, but will be restricted by the bolt (because the bolt…
- A 15" x 3/8" bar of A572 Gr. 50 steel is used as a tension member. It is connected to a gusset plate with 7/8-in diameter bolts as shown in the figure. Use s = 2.0 and g = 3.0. Determine the critical net area of the connection shown. Determine the design tensile strength of the section based on yielding of the gross area.A bracket cut from a W310X179 is connected to a W310X179 column flange with 12 A325 bearing-type bolts as shown in the figure. A 50 steel is used. The line of action of the load passes through the center of gravity of the connection. What size bolt is required? a. Use LRFD. b. Use ASD. D = 55k L = 145k I'-1" CS Scanned with CamScanner 22" 5 sp @ 4" てأ.د. رمضان المبروك A PL170mm x 10mm tension member is welded to a gusset plate as shown in Figure below. The steel is A36. Assume that Ae = Ag and compute the following. %3D fy = 250 MPa & f, = 400 MPa %3D %3D PL 170mmx10mm a. The design strength for LRFD. . The allowable strength for ASD. roblem (4):