VBased on advancements in drug therapy, a pharmaceutical company is developing Resithan, a new treatment for depression. Amedical researcher for the company is studying the effectiveness of Resithan as compared to their existing drug, Exemor. A randomsample of 414 depressed individuals is selected and treated with Resithan, and 191 find relief from their depression. A randomsample of 557 depressed individuals is independently selected from the first sample and treated with Exemor, and 213 find relieffrom their depression.Based on the medical researcher's study can we conclude, at the 0.05 level of significance, that the proportion p₁ of all depressedindividuals taking Resithan who find relief from depression is greater than the proportion p₂ of all depressed individuals takingExemor who find relief from depression?Perform a one-tailed test. Then complete the parts below.Carry your intermediate computations to three or more decimal places and round your answers as specified in the parts below. (Ifnecessary, consult a list of formulas.)(a) State the null hypothesis Ho and the alternative hypothesis H₁.0H₁ : DH₁ :0(b) Determine the type of test statistic to use.(Choose one)(c) Find the value of the test statistic. (Round to three or more decimal places.)0(d) Find the p-value. (Round to three or more decimal places.)ExplanationCheckμX0=00#0XOS060<0р02022 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | AccessibilityEspañol?AAa

It is given that n1 = 414, X1 = 191 n2 = 557, X2 = 213 Note: According to Bartleby expert…

(a) State the null hypothesis Ho and the alternative hypothesis H₁. Ho :D H₁₂ : 0 (b) Determine the type of test statistic to use. (Choose one) (c) Find the value of the test statistic. (Round to three or more decimal places.) (d) Find the p-value. (Round to three or more decimal places.) H X S 0=0 sa X OSO ☐#0 0<0 Ś