A student was instructed to determine the molecular weight of an unknown white powder. He remembered that one way to do this is by exploiting the colligative properties of solution. After a simple conductivity test, he found that an aqueous solution of the sample is not conductive. He dissolved 22.87 grams of the unknown sample in 0.500 kg of water. He found that the boiling point of the resulting solution was 100.13 OC under normal atmospheric conditions. Kb of water: 0.512 degrees celsius/m a. Calculate the molality of the resulting solution b. How many moles of the sample did he dissolve to perform the experiment? c. What is the molecular weight of the unknown sample?

Chemistry: An Atoms First Approach
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Author:Steven S. Zumdahl, Susan A. Zumdahl
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Chapter10: Properties Of Solutions
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Problem 31E: Common commercial acids and bases are aqueous solutions with the following properties: Density...
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A student was instructed to determine the molecular weight of an unknown white powder. He remembered that one way to do this is by exploiting the colligative properties of solution. After a simple conductivity test, he found that an aqueous solution of the sample is not conductive. He dissolved 22.87 grams of the unknown sample in 0.500 kg of water. He found that the boiling point of the resulting solution was 100.13 OC under normal atmospheric conditions.

Kb of water: 0.512 degrees celsius/m

a. Calculate the molality of the resulting solution
b. How many moles of the sample did he dissolve to perform the experiment?
c. What is the molecular weight of the unknown sample?

 

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