the peent in the mixture?If 15.0 mL of H2SO.are required to neutralize 25.0 mL of 0.660 N KOHa.solution, to what volume should 100 mL of the acid be diluted with water in orderfor the resulting solution to be 0.5 N?b.order for the resulting solution to be 0.700N as a base?2.What volume of 1.00 N NaOH should be added to a liter of the KOH inWhat volume of the diluted acid be neutralized by 25.1 mL of the alkaliC.mixture?A sample of KHP, KHC8H4O4, weighing 2.035 g is titrated with NaOH andbacktitrated with HCI. NAOH required = 23.20 mL; HCl required = 2.675 mL. Ifeach ml of HCI is equivalent (=) to 0.01600 g of Na20, what volume of 6.00 NNaOH must be added to 500 mL of above NaOH to bring it to 0.5000N?3.4.A sample of processed meat scrap weighing 4.000 g is digested withconcentrated H2SO4 and Hg(catalyst) until the N present has been converted toNH&HSO4. This is treated with excess NaOH, and the liberated NH3 is caught in a100-mL of H2SO4 ( 1mL = 0.01860 g Na20). The excess acid requires 57.60 mL ofNaOH ( 1mL = 0.12660 g potassium acid phthalate, KHC8H4O4). Calculate thepercentage protein in the meat scrapA 1.2 g sample of mixture of NaOH and NA2CO3 containing inert impurities sdissolved and titrated cold with 0.5N HCI. With phenolphthalein as indicator thesolution turns colorless after the addition of 30.0 mL of the acid. Methyl orange isthen added and 12 mL more of the acid is required before this indicatorchanges color. What is the percentage of NaOH and of Na2CO3 in the sample ?5.

These type of questions are based on the formula: M1V1 = M2V2 or N1V1 = N2V2 We will use the given…

a. If 15.0 mL of H2SO&are required to neutralize 25.0 mL of 0.660 N KOH solution, to what volume should 100 mL of the acid be diluted with water in order for the resulting solution to be 0.5 N? b. What volume of 1.00 N NaOH should be added to a liter of the KOH in order for the resulting solution to be 0.700N as a base? C. What volume of the diluted acid be neutralized by 25.1 mL of the alkali mixture? 2.

a. If 15.0 mL of H2SO&are required to neutralize 25.0 mL of 0.660 N KOH solution, to what volume should 100 mL of the acid be diluted with water in order for the resulting solution to be 0.5 N? b. What volume of 1.00 N NaOH should be added to a liter of the KOH in order for the resulting solution to be 0.700N as a base? C. What volume of the diluted acid be neutralized by 25.1 mL of the alkali mixture? 2.

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter16: Applications Of Neutralization Titrations

Section: Chapter Questions

Problem 16.48QAP

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