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why do these compounds show this trend in pka?
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- What is the structure of this molecule using this HNMR? C7H16O2a) Account for the pKa trend observed in these compounds. NH2 ÓCH3 THN" H2N CN CN pKa 8.54 7.80 5.342. Hemoglobin is a protein in red blood cells that contains iron and facilitates the transport of oxygen. The iron sits in the center of a heme ring in the form of Fe²+. The structure of a heme ring is here. H-C H-C H I H-C H H I C-N H-N-C C I C H C-N-H N-C C-H 1 C-H C-H H H a) The above structure is incomplete. Add electron pairs, non-zero formal charges, and/or additional bonds where needed to fulfill the octet rule to complete the structure. b) When Fe²+ is added to the structure in part a), the H atoms connected to the N are removed, see figure on the right. If you think of the heme ring as 4 N atoms, determine the molecular geometry of the new structure (you can draw it like [FeN4]2+). Imagine each N connects to Fe with a single bond. N- N Fe²+-N N
- 1. Which of the following compounds is separable by a physical method such as distillation? D A B.3. According to the Hammond Postulate, what does transition state 3 (TS3) most closely resemble? First choice: Second choice: AG (a) TS2 (b) P (c) 12 (d) 11 TS2 TS1 M 11 Reaction Coordinate 12 TS3Which molecule is labelled with the correct R and S descriptors? Br., R Br., R Br... S в кон ОА ов ос OD A R В S OH C OH R Br., S D S OH
- Kk.278. Please explain how to get the answerThere are three different dichloroethylenes (molecular for-mula C₂H₂Cl₂), which we can designate X, Y, and Z. CompoundX has no dipole moment, but compound Z does. Compounds Xand Z each combine with hydrogen to give the same product:C₂H₂Cl₂ (X or Z) +H₂→ClCH2-CH2Cl What are the structures of X, Y, and Z? Would you expect com-pound Y to have a dipole momenنقطتان )2( :Ksp of pbl2 equals [pb2+][12-] O [2pb+] [I-] O [pb2+] [I-] O [pb2+] [2l-] O
- What is the C-P bond order in BrCP?2. Calculate AH for the reaction; C₂H₂ (s) → 2 C (s) + H₂ (g), from the following Data; 1) CO2 (g) → C (s) +O2 (g) 2) 2 H₂O (1)→ → 2 2 H2 H2 (g) + O2 (g) 3) 2 C2H2 (s) + 5 O2 (g) → 4 CO2 (g) + 2 H₂O (1) ΔΗ = +394 kJ ΔΗ = +572 kJ AH = -2600 kJ5. Fill in the blanks: CH3 Cl 3 CH3 xs NCS Zn(Hg) Br HCI Br H3C H3C NBS Br, A FeBr, H3C ÇH3 H3C- ČH3