An object is V2= 3.13 m below the surface of the water. A laser y, = 1.29 m above the surface of the water and fires at an angle of 01= 26.5° to the horizontal. If the laser hits the target, what is the horizontal distance from the object to the laser? See fig. 3. target b. 4.42 m c. 4.94 m d. 5.42 m a. 5.66 m

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Chapter4: Diffraction
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Problem 7CQ: In Equation 4.4, the parameter looks like an angle but is not an angle that you can measure with a...
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An object is V2= 3.13 m below the surface of the water. A laser y, = 1.29 m above the surface of the
water and fires at an angle of 01= 26.5° to the horizontal. If the laser hits the target, what is the
horizontal distance from the object to the laser? See fig. 3.
%3D
target
b. 4.42 m
с. 4.94 m
d. 5.42 m
a. 5.66 m
Transcribed Image Text:An object is V2= 3.13 m below the surface of the water. A laser y, = 1.29 m above the surface of the water and fires at an angle of 01= 26.5° to the horizontal. If the laser hits the target, what is the horizontal distance from the object to the laser? See fig. 3. %3D target b. 4.42 m с. 4.94 m d. 5.42 m a. 5.66 m
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