Apply a perpendicularity tolerance tocontrol the pin within a 0.015" cylindricaltolerance zone at MMC relative to datumsurface. Pin length is 1.000", base diameteris 2.000". Finish the print.+.002-.001te-0.375DatumFeature

Answered: Apply a perpendicularity tolerance to…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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7. Calculate the minimum wall thickness between the inside diameter and datum feature B shown in the figure below. Datum B @ LMC: minus I. D. @ LMC: -Ø. minus Tolerance @ LMC: - Ø = The wall thickness equals half of the differences in diameters = Ø2.500 .020 4.059 ±.003 Ø2.000 .020 0.0200 ABO B I A Unless Otherwise Specified: .XXX = .010 ANGLES = ± 1° Figure for Problem 7
2. Nominal size is 40mm, the clearance is between 24µm and 92µm, the span of the clearance fit is not bigger than 68µm. To find out: O the upper/lower limit deviation of the hole; the upper/lower limit deviation of the shaft; ® the minimum clearance and the maximum clearance; Designation of fit; Illustration of tolerance interval/zone. The answer is as follows:
a) Three blocks A, B, and C and a grooved block D have dimensions a, b, c, and d as follows: a= 1.500 ± 0.001 in b= 2.000 ± 0.003 in c= 3.000 ± 0.004 in d= 6.520 ± 0.010 in Determine the mean gap ￣w and its tolerance. Determine the mean size of d that will assure that w ≥ 0.010 in. b) A 1-in-diameter rod, 3 ft long, of unknown material is found in a machine shop. A variety of inexpensive nondestructive tests are readily available to help determine the material, as described below with results in bracket: i. Visual inspection. (Dark gray, rough surface finish, moderate scale) ii. Check if it is attracted to a magnet. (Yes) iii. Measure Weight. (7.95lbf) iv. Inexpensive bending deflection test: Clamp one end in a vise, leaving 24 in cantilevered. (5/16in) v. Brinell hardness test. (HB = 200)
Problem (7): Determine tolerance value and limit dimension of the rod which a diameter is Ø25 mm, according to the limit deviation (Ø25H9). mkm, mkm. Determine the basic size, tolerance and limit dimensions.
Refer to the figure below. What is the MMC, LMC and geometric tolerance for the Hole and Pin: a. Hole: MMC LMC Geom. Tol. b. Pin: MMC LMC Geom. Tol. C 1.000 1 1.000 Ø.515-.540 Hole +0.010@ABC 1.000 B Ø.495-.500 Pin 0.005MABC A
Apply a perpendicularity tolerance to control the pin within a .005" cylindrical tolerance zone at MMC relative to the datum surface. +.002 0.375-001 Datum feature Calculate the virtual condition for the shown pin. A +.000 Ø.500 -.002 I0.003 A
For the geometrical tolerance feature shown, A=4.4, B=0.042, and C=0.00, +B A Compute the following: Basic size Tolerance Maximum limit size[ Minimum limit size 00
Problem (14): Determine tolerance value and limit dimension of the rod which a diameter is ∅127 mm, according to the g6 limit deviation (∅127f6). es=-40.64 mm, ei=-66.04 mm. Determine the basic size, tolerance and limit dimensions.
Question 2 A clearance fit between a Shaft and a Pulley is given as 15 H8-f7 (units in mm). Please refer to the Limits and Fits document from myUNISA additional resources; for convenience an excerpt o this table is provided on Page 5. Do the following: 2.1 State the nominal shaft size Using the ISO Limits/Fits table, determine the upper and lower tolerance for the shaft. (Hint, consider the H8 designation and make sure units are correct) 2.2 Using the ISO Limits/Fits table, determine the upper and lower tolerance for the hole (bearing). (Hint, consider the f7 designation and make sure units are correct) 2.3
A rectangular block 100 mm x 150 mm has a hole with diameter 60 mm at the center. The hole tolerance zone is H7. The thickness of the block is 45 mm. The virtual condition is: O 60.03 mm O 60.02 mm O 59.98 mm O 59.97 mm
Given a pin with a size dimension of Ø.875±.003 and a perpendicularity tolerance of .002 at MMC to a primary datum, what is the boundary that takes into consideration the combined effect of feature size at MMC and the geometric tolerance? .870 .874 .876 .880
7. Calculate the minimum wall thickness between the inside diameter and datum feature B shown in the figure below. Datum B @ LMC: Ø -Ø minus I. D. @ LMC: minus Tolerance @ LMC: - Ø. = The wall thickness equals half of the differences in diameters = Ø2.500 .020 4.059 +.003 Ø2.000 .020 +0.0200 ABO B A Unless otherwise Specified: .XXX= .010 ANGLES = ± 1°

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Apply a perpendicularity tolerance to control the pin within a 0.015" cylindrical tolerance zone at MMC relative to datum surface. Pin length is 1.000", base diameter is 2.000". Finish the print.