Explain solution please PAKa 9 = 0.219 x 408.76 KN/mAt A,At B,PBKa q + Ka Y Z8.76 + 0.219 x 19 X 2O91.98 KN/mA 8.7620 mPz- 83. 22.91.98.. Active eareth pressure8.76 x 20P,175.2 KN/m = 10 m aboreact at 20bajeandP, =5x20x 83.228 32.2 KN/M act at 203abore= 666 mbase Total active earth preessureP = Pi + P2175.2 + 832.2%3D1007.4 KN/mactivewill be act atThePressure175.2 X10 +832, 2 x 6.66h=lo07.47,24 mabove base

this is the active case in cohesion soilfirst of all you have to determine,active earth pressure at…

At A , PA = Ka 9 : 0:219 x40 %3D 8.76 KN/m At B, Ka 9 + Ka Y Z 8.76+ 0.219 x 19 x 20 %3D 91.98 KN/m %3D A 8.76 20 m P, K Pz 83. 22 91.98 Active eareth preessure P, 8.76 x 20 175.2 KN/m act at 20 = = 10 m abonre base Ond Ivan Y 83,22

At A , PA = Ka 9 : 0:219 x40 %3D 8.76 KN/m At B, Ka 9 + Ka Y Z 8.76+ 0.219 x 19 x 20 %3D 91.98 KN/m %3D A 8.76 20 m P, K Pz 83. 22 91.98 Active eareth preessure P, 8.76 x 20 175.2 KN/m act at 20 = = 10 m abonre base Ond Ivan Y 83,22

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Question

Explain solution please

PA
Ka 9 = 0.219 x 40
8.76 KN/m
At A,
At B,
PB
Ka q + Ka Y Z
8.76 + 0.219 x 19 X 2O
91.98 KN/m
A 8.76
20 m
Pz
- 83. 22.
91.98
.. Active eareth pressure
8.76 x 20
P,
175.2 KN/m = 10 m abore
act at 20
baje
and
P, =5x20x 83.22
8 32.2 KN/M act at 20
3
abore
= 666 m
base

Total active earth preessure
P = Pi + P2
175.2 + 832.2
%3D
1007.4 KN/m
active
will be act at
The
Pressure
175.2 X10 +
832, 2 x 6.66
h=
lo07.4
7,24 m
above base

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