b. Calculate the equilibrium constant, K, at 298 K for the reaction using AG° = -RT In K. 4 Ag(s) + O2(g) + 4 H*(aq) → 4 Ag*(aq) + 2 H2O(1) O2(g) + 4 H*(aq) + 4 e- +1.23 → 2 H2O(1) Br2(1) + 2 e NO, (aq) + 4 H*(aq) + 3 e → NO(g) + 2 H20(1) +1.06 2 Br (aq) - +0.96 Ag*(aq) + e¯ Ag(s) +0.80 Do the signs/values of AG° and K make sense for this reaction given the cell potential?

Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter17: Electrochemistry And Its Applications
Section: Chapter Questions
Problem 66QRT
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How do you do (b) and (c)?

b. Calculate the equilibrium constant, K, at 298 K for the reaction
using AG° = -RT In K.
4 Ag(s) + O2(g) + 4 H*(aq) → 4 Ag*(aq) + 2 H2O(1)
O2(g) + 4 H*(aq) + 4 e-
+1.23
→ 2 H2O(1)
Br2(1) + 2 e
NO, (aq) + 4 H*(aq) + 3 e → NO(g) + 2 H20(1)
+1.06
2 Br (aq)
-
+0.96
Ag*(aq) + e¯
Ag(s)
+0.80
Do the signs/values of AG° and K make sense for this reaction
given the cell potential?
Transcribed Image Text:b. Calculate the equilibrium constant, K, at 298 K for the reaction using AG° = -RT In K. 4 Ag(s) + O2(g) + 4 H*(aq) → 4 Ag*(aq) + 2 H2O(1) O2(g) + 4 H*(aq) + 4 e- +1.23 → 2 H2O(1) Br2(1) + 2 e NO, (aq) + 4 H*(aq) + 3 e → NO(g) + 2 H20(1) +1.06 2 Br (aq) - +0.96 Ag*(aq) + e¯ Ag(s) +0.80 Do the signs/values of AG° and K make sense for this reaction given the cell potential?
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