B. Heat of neutralization for NaOH (aq) (AH(neut. NaOH(aq)) Mass NaOH = 1.022 g (From part 1) Moles NaOH = Mass of solution in cup Final temp. of solution Initial temp. of solution AT solution. (AH(neut. NaOH (aq)) = = AH(neut. NaOH (aq)) per mole NaOH = Calculation AH (neut. NaOH (s)) AH (neut. NaOH (s)) per mole NaOH = = 0.026 600 mL 30°C 24°C C. Heat of neutralization for NaOH (s) (AH(neut. NaOH (s)) Mass of solution in cup 30mL Final temp. of solution in cup Initial temp. of solution in cup AT solution in cup Calculation = 30°C-24°C 6°℃ moles 420 25.0°C 42°C-25°C = 14°C
B. Heat of neutralization for NaOH (aq) (AH(neut. NaOH(aq)) Mass NaOH = 1.022 g (From part 1) Moles NaOH = Mass of solution in cup Final temp. of solution Initial temp. of solution AT solution. (AH(neut. NaOH (aq)) = = AH(neut. NaOH (aq)) per mole NaOH = Calculation AH (neut. NaOH (s)) AH (neut. NaOH (s)) per mole NaOH = = 0.026 600 mL 30°C 24°C C. Heat of neutralization for NaOH (s) (AH(neut. NaOH (s)) Mass of solution in cup 30mL Final temp. of solution in cup Initial temp. of solution in cup AT solution in cup Calculation = 30°C-24°C 6°℃ moles 420 25.0°C 42°C-25°C = 14°C
Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter8: Thermochemistry
Section: Chapter Questions
Problem 12QAP: The heat of neutralization, Hneut, can be defined as the amount of heat released (or absorbed), q,...
Related questions
Question
Transcribed Image Text:B. Heat of neutralization for NaOH (aq) (AH(neut. NaOH(aq))
Mass NaOH = 1.022 g (From part 1) Moles NaOH =
Mass of solution in cup
Final temp. of solution
Initial temp. of solution
AT solution.
(AH(neut. NaOH (aq)) =
=
AH(neut. NaOH (aq)) per mole NaOH =
Calculation
AH (neut. NaOH (s))
AH (neut. NaOH (s)) per mole NaOH =
= 0.026
600 mL
30°C
24°C
C. Heat of neutralization for NaOH (s) (AH(neut. NaOH (s))
Mass of solution in cup
30mL
Final temp. of solution in cup
Initial temp. of solution in cup
AT solution in cup
Calculation
=
30°C-24°C 6°℃
moles
420
25.0°C
42°C-25°C = 14°C
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 4 steps with 14 images
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Recommended textbooks for you
Chemistry: Principles and Reactions
Chemistry
ISBN:
9781305079373
Author:
William L. Masterton, Cecile N. Hurley
Publisher:
Cengage Learning
Introduction to General, Organic and Biochemistry
Chemistry
ISBN:
9781285869759
Author:
Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Publisher:
Cengage Learning
Chemistry: Principles and Reactions
Chemistry
ISBN:
9781305079373
Author:
William L. Masterton, Cecile N. Hurley
Publisher:
Cengage Learning
Introduction to General, Organic and Biochemistry
Chemistry
ISBN:
9781285869759
Author:
Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Publisher:
Cengage Learning
Principles of Modern Chemistry
Chemistry
ISBN:
9781305079113
Author:
David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Publisher:
Cengage Learning
Introductory Chemistry: A Foundation
Chemistry
ISBN:
9781337399425
Author:
Steven S. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning