BA simply supported beam carries a unifromly distributed load of intensity 30 N/mm over the entire span of 1 m. The cross- section of the beam is a T-section having the dimension as shown in Fig. 4. Calculate the maximum shear stress for the section of the beam. -125 mm- 25 175 'mm 25 mm

Elements Of Electromagnetics
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BA simply supported beam carries a unifromly distributed load
of intensity 30 N/mm over the entire span of 1 m. The cross-
section of the beam is a T-section having the dimension as
shown in Fig. 4. Calculate the maximum shear stress for the
section of the beam.
-125 mm-
25
175 'mm
25 mm
Transcribed Image Text:BA simply supported beam carries a unifromly distributed load of intensity 30 N/mm over the entire span of 1 m. The cross- section of the beam is a T-section having the dimension as shown in Fig. 4. Calculate the maximum shear stress for the section of the beam. -125 mm- 25 175 'mm 25 mm
Q1 A A simply supported beam carries a UDL of 25 kN/m over
the entire span of the beam is shown in Fig. 6. If the maximum
bending stress is 60 MPa, find the span of the beam. Also
find the maximum shear stress developed in the section. Draw
the shear stress distribution diagram.
200mm
,w = 25kN/m
50mm
- 250mm
(a)
(b)
B Derive the flexure (Bending) formula.
Transcribed Image Text:Q1 A A simply supported beam carries a UDL of 25 kN/m over the entire span of the beam is shown in Fig. 6. If the maximum bending stress is 60 MPa, find the span of the beam. Also find the maximum shear stress developed in the section. Draw the shear stress distribution diagram. 200mm ,w = 25kN/m 50mm - 250mm (a) (b) B Derive the flexure (Bending) formula.
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