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- Available whis.picture. https://www.phys.ksu.edu/gene/photos/sd.html.g will help vou imagine the results for plateAvailable (C hope this picture, https:://www.phys.ksu.edu/gene/photos/sd.html,e will help you imagine the results for platelSearch (Option + Q) rences Review View Help Editing v A^ Dv A A A Question 1 During nucleic acid hybridization, the probe is labelled for DNA stability to increase probe-test DNA binding to identify the location of probe and the test DNA binding for amplification Question 2 10 IV 12 13 14 Which of the following best describes the trait in the pedigree? Question 2 options: X-linked dominant X-linked recessive autosomal domiant autosomal recessive
- ersonal/eenongen_my_tnstate_edu/_layouts/15/doc.aspx?sourcedoc={a6b083c9-a226-4c31... ☆ Search (Option + Q) Review View Help Picture Editing A В ... During nucleic acid hybridization, the probe is labelled Question 1 options: for DNA stability to increase probe-test DNA binding to identify the location of probe and the test DNA binding for amplification Question 2 6. 9. 10 IV 13 14 Which of the following best describes the trait in the pedigree? Question 2 options: X-linked dominant X-linked recessive autosomal domiant autosomal recessive ONpersonal/eenongen_my_tnstate_edu/_layouts/15/doc.aspx?sourcedoc={a6b083c9-a226-4c31... O Search (Option + Q) Review View Help Editing v A BI U Ov =<=v 三 v ... Question 13 Zinc finger nuclease is a Gene editing tool: which uses a site-specific endonucleases containing a DNA-cleavage domain and a modular DNA-binding domain RNA-guided endonucleases programmable nucleases Exonuclease Question 14 Which elements are required for DNA to behave as a chromosome in yeast cells: a centromere an autonomous replicating sequence two telomeres Antibiotic selection marker Question 15 A series of such clones where the insert of each clone partially overlaps that of its neighbors with no gaps is known as a Clone Contig DNA fingerprinting A tiling path Genome MacBook ProQuestion 9 Review concepts 21.5-21.6. Match term and its description. the mechanism contributes to polyploidy | Choose ) rearrangements of parts of genes due to meiotic errors |Choose one or multiple copies of a gene or genetic regions at loci in some | Choose J humans consequence of duplication, rearrangement and mutation of DNA [Choose J
- Search (Option + Q) Review View Help Editing v B IU ev Av A =<而< 面 三< A Question 16 The full set of different transcripts expressed by a cell is called Proteome Genome Transcriptome Glycome Question 17 One of the major drawback of using Microarray over RNA sequencing for high throughput sequence analysis is allows quantification of transcripts over five orders of magnitude usei to identify new transcripts and alternative isoforms RNA-Seq is sensitive and offers a way of profiling transcripts of single cells a significant amount of input RNA is required Question 18 Which of these statements are not true for the DNA libraries: Genomic DNA libraries are collection of cloned DNA fragments representing the genome from an organism. Genomic DNA is completely (fully) digested with restriction endonuclease. Complementary DNA (CDNA) libraries are derived from reverse transcribed RNA Genomic DNA is partially digested with restriction endonuclease.1. You are investigating a protein that has the amino acid sequence N ... Ala – Thr - Asn – Trp – Lys - Arg - Gly – Phe – Thr ... C within its primary structure. You found that several of the mutations affecting this protein produced shortened protein molecules that terminated within this region. In one of the mutants, the Asn became the terminal (last) amino acid. (a) What DNA single-base changes(s) would cause the protein to terminate at the Asn residue? (b) What other potential sites do you see in the DNA sequence encoding this protein where mutation of a single base pair would cause premature termination of translation? >BIOINFORMATICS Please solve the questions about(Akt 1) can use NCBI Please help me 1.What is the official genename of the gene? Do you have another names? 2.Find nucleotide sequence of reference sequence of your gene. 3.Find refseq transcript number of your gene. Make BLAST of two of refseq transcript. Show the Blast result. (You can take screenshots) 4.Find refseq protein sequence number of your gene. And download the amino acid sequence of your gene. 5.What is the chromosome number is it located? 6.What are the coordinates of the gene? 7.How many bp is the length of the transcript? (Hint: not RefSeq transcript) 8.What is the transcript access number? 9.How many exons and introns does it have? 10. What is the sequence of the first exon? 11.How many nucleotides long is each exon? 12. What is the UniProt accesion number of your genes for human?
- patibility Mode] UE Layout References Mailings Review View A A Aa vA 前、一间刷 一| T AaBbCcDdE AaBE x A Av X, Normal No Spacing Headi co Edit and Save Start your free one month trial of Microsoft 365 or sign in to activate an existing subscription. 9. In human beings, the gene for red-green colorblindness (r) is sex-linked and recessive to its allele for normal vision (R), while the gene for freckles (F) is autosomal and dominant over its allele for nonfreckled (f). A nonfreckled, normal-visioned woman whose father was freckled and colorblind, marries a freckled, colorblind man whose mother was nonfreckled. a. What is the genotype of the woman's father? b. What is the probability that the couple's first child will be a non-freckled, normal visioned girl c. What is the probability that the first two children born to the couple will be freckled and colorblind girls? d. What is the probability that the first child born to the couple will either be a freckled, colorblind boy or a non-freckled,…וןווד ← Q Lab Report 6 worksheets 314 F22 .DOCX File Edit View Insert Format Tools Help A 100% ¿ Summary Grades for Arysta Visser: 23 x M Uh-oh! There's a problem w X b The restriction EcoRI cleaves X + Untitled spreadsheet - Goog X https://docs.google.com/document/d/1mKY1HIgMPRh1kRDCmX7msBF2yf07-ogT/edit Outline Headings you add to the document will appear here. Normal text Times ... 12 + B I U 2 18. The restriction EcoRI cleaves double-stranded DNA at the sequence 5'-GAATTC-3', the restriction enzyme HindIII cleaves at the sequence 5'-AAGCTT-3', and the restriction enzyme BamHI cleaves at 5'GGATCC-3. An 805 bp circular plasmid is digested with each enzyme individually and then in combination, and the resulting fragment sizes are determined by means of electrophoresis. The results are as follows: 1 Restriction Enzyme(s) EcoRI BamHI HindIII EcoRI and BamHI EcoRI and HindIII BamHI and HindIII 3 Practice ====•=•€ EX Fragment lengths (base pairs) 430 bp, 375 bp 470 bp, 335 bp Lab Report 6…15/doc.aspx?sourcedoc={dac0ebeb-b019-4578-911c-98.. Search (Option + Q) Review View Help Table O Editing er Av A =SEE MORE QUESTIONS