Calculate the all-day efficiency of a 100-KVA transformer operating under the following conditions: 6 hour, 50 kW, 0.73 pf 3 hours, 90 kW, 0.82 pf Iron loss = 1000 watts One quarter load Copper loss = 66.25 watts a) The rest of the day, transformer running idle b) The rest of the day, primary disconnected from the source.
Calculate the all-day efficiency of a 100-KVA transformer operating under the following conditions: 6 hour, 50 kW, 0.73 pf 3 hours, 90 kW, 0.82 pf Iron loss = 1000 watts One quarter load Copper loss = 66.25 watts a) The rest of the day, transformer running idle b) The rest of the day, primary disconnected from the source.
Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN:9781305632134
Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Chapter3: Power Transformers
Section: Chapter Questions
Problem 3.16MCQ: In developing per-unit circuits of systems such as the one shown in Figure 3.10. when moving across...
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Calculate the all-day efficiency of a 100-KVA transformer operating under the following conditions:
6 hour, 50 kW, 0.73 pf
3 hours, 90 kW, 0.82 pf
Iron loss = 1000 watts
One quarter load Copper loss = 66.25 watts
a) The rest of the day, transformer running idle
b) The rest of the day, primary disconnected from the source.
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