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Calculate the braking moment of the measured brake, using first approach if you know that P0 [N]=50N, μ=0.4 and length of loaded spring – L1=190mm.

Calculate the braking moment of the measured brake, using first approach if you know that P0 [N]=50N, μ=0.4 and length of loaded spring – L1=190mm.

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Calculate the braking moment of the measured brake, using first approach
if you know that P0 [N]=50N, μ=0.4 and length of loaded spring – L1=190mm.

2.Theoretical and Experimental Research 2.1 Experimental measurements 2.1.1 Spring Load of the spring – m = 30kg Free length of the spring – Lo = 136mm Length of loaded spring – L1 = 128mm Number of coils – i = 12 m [kg] Diameter of the material – d = 5mm Average spring radius – r = 12.2mm 2.1.2 Brake 2.1.2.1 Brake Spring Free length of the spring – Lo = 205mm Number of coils – i = 9 Diameter of the material – d = 8mm Average spring radius- r = 26mm Diameter of braking drum – D = 295mm Lever 1 length -L = 450mm Lever 2 length – L1 = 180mm 01 otosiMF
Transcribed Image Text:2.Theoretical and Experimental Research 2.1 Experimental measurements 2.1.1 Spring Load of the spring – m = 30kg Free length of the spring – Lo = 136mm Length of loaded spring – L1 = 128mm Number of coils – i = 12 m [kg] Diameter of the material – d = 5mm Average spring radius – r = 12.2mm 2.1.2 Brake 2.1.2.1 Brake Spring Free length of the spring – Lo = 205mm Number of coils – i = 9 Diameter of the material – d = 8mm Average spring radius- r = 26mm Diameter of braking drum – D = 295mm Lever 1 length -L = 450mm Lever 2 length – L1 = 180mm 01 otosiMF
2.2.2.1 First approach for determine the braking moment If we know that : P1 = CT.6 [N] Where: P1 [N] – Force on the main spring of the brake; CT [N/m] – Theoretical elastic factor of the main spring of the brake; 8 [m] – Deformation of the main spring of the brake. Braking moment will be: (P – Po). µ. D. L [Nm] Mpri L1 Where: P1 [N] – Force in the main spring; Po [N] – Force in the secondary spring; H - theoretical friction factor between brake pad and drum; D (m] – drum diameter; L [m] – length of the first lever; L1 [m] – length of the second lever. Soffa MF
Transcribed Image Text:2.2.2.1 First approach for determine the braking moment If we know that : P1 = CT.6 [N] Where: P1 [N] – Force on the main spring of the brake; CT [N/m] – Theoretical elastic factor of the main spring of the brake; 8 [m] – Deformation of the main spring of the brake. Braking moment will be: (P – Po). µ. D. L [Nm] Mpri L1 Where: P1 [N] – Force in the main spring; Po [N] – Force in the secondary spring; H - theoretical friction factor between brake pad and drum; D (m] – drum diameter; L [m] – length of the first lever; L1 [m] – length of the second lever. Soffa MF
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