Carbon dioxide and water react to form methane and oxygen, like this: CO,(9)+2H,O(9) → CH,(9)+2O3(9) The reaction is endothermic. Suppose a mixture of CO,, H,O, CH, and O, has come to equilibrium in a closed reaction vessel. Predict what change, if any, the perturbations in the table below will cause in the composition of the mixture in the vessel. Also decide whether the equilibrium shifts to the right or left. perturbation change in composition shift in equilibrium to the right The temperature is lowered. O to the left The pressure of H20 will ? (none) the right The temperature is raised. The pressure of CH4 will O to the left ? O (none)

Principles of Modern Chemistry
8th Edition
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Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
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Chapter14: Chemical Equilibrium
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Carbon dioxide and water react to form methane and oxygen, like this:
CO2(9)+2H,O(g)
CH4(9)+202(g)
→
The reaction is endothermic. Suppose a mixture of CO2, H,0, CH, and O, has come to equilibrium in a closed reaction
vessel. Predict what change, if any, the perturbations in the table below will cause in the composition of the mixture in the
vessel. Also decide whether the equilibrium shifts to the right or left.
perturbation
change in composition
shift in equilibrium
to the right
The temperature is
lowered.
to the left
The pressure of H,0 will
?
(none)
to the right
to the left
The temperature is raised. The pressure of CH4 will
(none)
Transcribed Image Text:Carbon dioxide and water react to form methane and oxygen, like this: CO2(9)+2H,O(g) CH4(9)+202(g) → The reaction is endothermic. Suppose a mixture of CO2, H,0, CH, and O, has come to equilibrium in a closed reaction vessel. Predict what change, if any, the perturbations in the table below will cause in the composition of the mixture in the vessel. Also decide whether the equilibrium shifts to the right or left. perturbation change in composition shift in equilibrium to the right The temperature is lowered. to the left The pressure of H,0 will ? (none) to the right to the left The temperature is raised. The pressure of CH4 will (none)
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