Change in pH = b 0.0680 M HCI. Change in pH = C 0.0680 M NAOH. Change in pH =

Fundamentals Of Analytical Chemistry
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Chapter14: Principles Of Neutralization Titrations
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Problem 14.36QAP
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Calculate the change in pH that occurs when 1.10 mmol of a strong base is added to 100 mL of the solutions listed below., Calculate values to three
decimal places.
thiem requlres values in your textbook's specific appendices, which you can access through the OWLV2 MindTap Reader. You
wll nat match.)
Transcribed Image Text:Calculate the change in pH that occurs when 1.10 mmol of a strong base is added to 100 mL of the solutions listed below., Calculate values to three decimal places. thiem requlres values in your textbook's specific appendices, which you can access through the OWLV2 MindTap Reader. You wll nat match.)
a H,0.
Change in pH =
b0.0680 M HCI.
Change in pH =
C0.0680 M NaOH.
Change in pH =
d.0680 м СН, СН, CH, СООН.
Change in pH =
е 0.0680 м СHН, СНСH СООNa.
Change in pH =
f0.0680 M CH3 CH2 CH2COOH + 0.0680 M CH3 CH, CH2 COONA.
Change in pH =
9 0.680 M CH3 CH2CH, COOH + 0.680 M CH3 CH2 CH2COONA.
Change in pH =
Transcribed Image Text:a H,0. Change in pH = b0.0680 M HCI. Change in pH = C0.0680 M NaOH. Change in pH = d.0680 м СН, СН, CH, СООН. Change in pH = е 0.0680 м СHН, СНСH СООNa. Change in pH = f0.0680 M CH3 CH2 CH2COOH + 0.0680 M CH3 CH, CH2 COONA. Change in pH = 9 0.680 M CH3 CH2CH, COOH + 0.680 M CH3 CH2 CH2COONA. Change in pH =
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