Compute for the sum/difference/product/quotient, then let the final answer follow correct significant figures 1. 90.09 +23.4232 +0.23= 2. 0.000392 0.000023897 = 3. 9.00*0.012= 4. 8594.32/23 - 5. 1.23 x 1023/90.239 =
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- a .ull Asiacel| 10 N 141 N O A box with a volume (V=0.05 m³) lies at the bottom of a lake whose water has a density of (1*10³ kg/m³). How much force is required to lift the box, .if the mass of the box is (1000 kg) 9319.5 N O 9313.9 N O 9391.5 N O 9315.9 N O A future rectangular ship filled with oil. If the dimensions of the ship are (250 m) long, (80 m) wide, and (80 m) high. Determine how far the bottom of the ship is below the sea level? (Consider the total mass of the ship with the oil is (10.2*108 kg), and the .sea density is (1024 kg/m³))What is the boiling point of the unknown substance Xin K(Kelvin)? X(t) = X(g) AH-(kJ mol1) S°J mol1K1) X(g) -82.0 238 | X({) | -101 144 Express your answer in decimal notation rounded to three significant figures.Calculate the electrostatic force of repulsion for two protons separated by 93.0 pm. The charge of a proton is q = 1.6 x 10-1⁹ C. Express your answer to two significant figures and include the appropriate units. Fel = μA 2.7.10 6 Submit N Previous Answers Request Answer ? X Incorrect; Try Again; 5 attempts remaining Use the equation Fel = K(Q₁ Q₂/d²) to find the electrostatic force between the two particles. Q₁ and Q2 are the charges on the particles (charge of a proton here), and d is the distance of separation. The constant is given in the introduction and has the units Nm²/C². This means that the distance must be converted from picometers to meters using the relation 1 pm = 1 × 10¯ m. -12
- Powers of 10 - multiply Solve for the variables below. a. 769.17× 10² 7.6917 p= b. 881.73× 10¯4=j j=Use the References to access important values if needed for this question. Two-Step Algebra 1 1 bc + d In order to solve the equation above for b, you must: Step One Add the same expression to each side of the equation to leave the term that includes the variable by itself on the right-hand side of the expression: 1 + - = a +bc + - dWhy does the x go from:-0.9968x = -0.0025To:x= 0.0025x/0.9968And not:x= 0.9968/0.0025Wouldn't the negatives simply be ignored and the x would remain with:0.9968x and then you divide then 0.0025 without the coefficient x to get the value of x by cancelling out the 0.9968?
- 1) State your interpretation of the meaning of the slope for the first graph you prepared of Volume of Steel Nuts (mL) versus Number of Steel Nuts. Hint: Understanding the meaning of a slope involves several factors: the units which are a ratio of the y axis units over the x axis units, the interpretation of the slope as “number of the y axis units for every one of the x axis units” and the concept that constructing the best line or curve that follows the trend in the data is a sort of averaging of the random error throughout the data.1. Refer to the hexagon pattern below. Assume that each edge of the hexagon measures 1 cm. Assume that one hexagon is added to one shape to get the next shape. Let H(n) be the function describing the perimeter as a function of the shape number. Shape 1: Shape 2: Shape 3: (a) Draw the next two shapes in the pattern. 1, 2, 3, 4, and 5 and make a graph of the values (b) Make a table with columns for n and H(n) for n = in your table. (c) Write an equation for H(n).4/3 pie * (0.0576/2)^3=0.00010061=1.00=1.00x2.20/60.02=0.036654449*60.09=2.202565811=2.2E-18 ? is this even right? i've been struggling with this problem for hours.
- The result of (3.8621 * 1.5630) - 5.98 is properly written asSystematic error causes the mean of a data set to differ from the accepted value. True Falsea .ll Asiacel| 10 N 141 N O A box with a volume (V=0.05 m³) lies at the bottom of a lake whose water has a density of (1*10³ kg/m³). How much force is required to lift the box, .if the mass of the box is (1000 kg) 9319.5 N O 9313.9 N O 9391.5 N O 9315.9 N O A future rectangular ship filled with oil. If the dimensions of the ship are (250 m) long, (80 m) wide, and (80 m) high. Determine how far the bottom of the ship is below the sea level? (Consider the total mass of the ship with the oil is (10.2*108 kg), and the .sea density is (1024 kg/m³))