Computer science questions

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Which represents a tight upper bound on the runtime of the following code using Big-O notation:
sum = 0;
for (int i = 0; i < n/2; i += 3) {
%3D
for (int j
1; j < n; j *= 3) {
%3D
}
}
O(n)
O(n)
O(logn)
O(nlogn)
O(1)
Transcribed Image Text:Which represents a tight upper bound on the runtime of the following code using Big-O notation: sum = 0; for (int i = 0; i < n/2; i += 3) { %3D for (int j 1; j < n; j *= 3) { %3D } } O(n) O(n) O(logn) O(nlogn) O(1)
Which choice below represents code to change these circularly linked nodes:
front -> node1 -> node2 -> node3 -> node1
Into this:
front -> node3 -> node2 -> node1 -> null
In both cases, front is a variable of type Node referring to the front of the chain of nodes. (The
definition of the Node class appears below as a reference.)
Here is the code that produces the circularly linked group of nodes shown in the upper diagram:
NodecInteger> front = new NodecInteger> (3, null);
front = new Node<Integer>(2, front);
front = new Node<Integer>(1, front);
front.next.next.next = front;
Here is the Node class:
public class NodecE> {
protected E element;
protected NodecE> next;
public Node() {
element = null;
next = null;
public Node(final E theElement, final NodecE> theSuccessor) {
element = theElement;
next = theSuccessor;
front = front.next;
front.next.next = front;
front = front.next;
front.next.next = null;
front = front.next.next;
front.next = front.next.next;
front.next.next = front.next;
front.next.next.next = null;
front = front.next.next;
front.next.next.next = front.next;
front.next.next.next = null;
front.next - front.next.next;
front = front.next.next;
front.next.next.next = front.next;
front.next = front.next.next;
front.next.next.next = null;
Transcribed Image Text:Which choice below represents code to change these circularly linked nodes: front -> node1 -> node2 -> node3 -> node1 Into this: front -> node3 -> node2 -> node1 -> null In both cases, front is a variable of type Node referring to the front of the chain of nodes. (The definition of the Node class appears below as a reference.) Here is the code that produces the circularly linked group of nodes shown in the upper diagram: NodecInteger> front = new NodecInteger> (3, null); front = new Node<Integer>(2, front); front = new Node<Integer>(1, front); front.next.next.next = front; Here is the Node class: public class NodecE> { protected E element; protected NodecE> next; public Node() { element = null; next = null; public Node(final E theElement, final NodecE> theSuccessor) { element = theElement; next = theSuccessor; front = front.next; front.next.next = front; front = front.next; front.next.next = null; front = front.next.next; front.next = front.next.next; front.next.next = front.next; front.next.next.next = null; front = front.next.next; front.next.next.next = front.next; front.next.next.next = null; front.next - front.next.next; front = front.next.next; front.next.next.next = front.next; front.next = front.next.next; front.next.next.next = null;
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