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Consider a cross between a Brown furred dog and a Yellow furred dog. All the puppies born from these parents are yellow furred. Crossing the F1 yellow furred sons and F1 yellow furred daughters produces a 3:1 ratio of yellow furred dogs (3) to brown-furred dogs (1) in the F2 generation.
True or False: this tells you that brown fur color in this dog species is inherited in an autosomal recessive manner.
is it true or false?
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- Two different autosomal loci (t1 and t2) can render a mouse tailless. The tailless alleles at both loci are recessive. Homozygosity for the recessive allele at either of the loci or at both loci renders the mouse tailless. A tailless mouse homozygous for t1 is mated to a tailless mouse that is homozygous for t2 and produces F1 mice with NORMAL tails. What will be the ratio of tailed:tailless mice in the F2?Color blindness in humans is controlled by an X-linked completely recessive allele (Xc), while breast cancer is controlled by an autosomal completely dominant allele, B. A color blind male, who is a heterozygote carrier for breast cancer has three children/n with a normal eyed female (whose mother was color blind), who is homozygote recessive for the breast cancer allele. What is the probability that out of three children, 2 will be color blind males, and not show breast cancer, and one will be a color blind female, who shows breast cancer?In humans, ABO blood types refer to glycoproteins in the membranes of red blood cells. There are three alleles for this autosomal gene: IA, IB, and i. The IA allele codes for the A sugar, The IB allele codes for the B sugar, and the i allele doesn't code for any sugar. IA and IB are codominant, and i is recessive to both IA and IB. If an individual with type AB blood has a child with an individual with type O blood, what blood types could their children possibly have?
- For the following cross, show the P generation Genotypes and the Phenotypic ratio that would be seen in the F1 and F2. Remember, to produce the F2 generation you want to cross Heterozygotes from the F1. d) Genes 1 and 2 exhibit Epistasis (9:6:1) and Gene 3 is an Autosomal Dominant. In the P generation, the Male is Homozygous Recessive for the Genes showing Epistasis. Use E1, E2 and E3 to represent the Phenotypes shown by Epistasis. Report your results in the following format: P = aabb x AABB, F1 = 100%AaBb (Phenotype), and %3! F2 = 9/16 A_B_ (Phenotype), 3/16 aaB (Phenotype), 3/16 A_bb (Phenotype), 1/16 aabb (Phenotype)In the snail Cepaea nemoralis, an autosomal allele causing a banded shell (BB) is recessive to the allele for an unbanded shell (BO). Genes at a different locus determine the background color of the shell; here, yellow (CY) is recessive to brown (CBw). A banded, yellow snail is crossed with a homozygous brown, unbanded snail. The F1 are then crossed with banded, yellow snails (a testcross). a. What will the results of the testcross be if the loci that control banding and color are linked with no crossing over? b. What will the results of the testcross be if the loci assort independently? c. What will the results of the testcross be if the loci are linked and 20 m.u. apart?In the snail Cepaea nemoralis, an autosomal allele causing a banded shell (BB) is recessive to the allele for an unbanded shell (BO). Genes at a different locus determine the background color of the shell; here, yellow (CY) is recessive to brown (CBw). A banded, yellow snail is crossed with a homozygous brown, unbanded snail. The F1 are then crossed with banded, yellow snails (a testcross). Q.What will the results of the testcross be if the loci are linked and 20 m.u. apart?
- In the snail Cepaea nemoralis, an autosomal allele causing a banded shell (BB) is recessive to the allele for an unbanded shell (BO). Genes at a different locus determine the background color of the shell; here, yellow (CY) is recessive to brown (CBw). A banded, yellow snail is crossed with a homozygous brown, unbanded snail. The F1 are then crossed with banded, yellow snails (a testcross). Q.What will the results of the testcross be if the loci that control banding and color are linked with no crossing over?In owl, barring (B) is sex-linked and dominant, the recessive allele (b) producing solid black color when homozygous. Silky feathers (s) is a recessive autosomal gene, as opposed to non-silky (S). If black cocks, heterozygous for non-silky, are crossed to barred, silky hens, what genotypes and phenotypes will be produced? (Sex linked genes can be written as XAXA for female and XAY for male since superscript function are not available) what is the genotype of the cock? What are the possible genotypes of the hen? Write the genotypes of the F1 when the hen is homozygous dominant for barring What is the phenotypic ratio? What is the genotypic ratio when the hen is heterozygous for barring? How many female carriers are present when the hen is heterozygous for barring? (use fraction)Red-green color blindness is inherited as an X-linked recessive (Xc). If a color-blind man marries a woman who is heterozygous for normal vision, what would be the expected phenotypes of their children with reference to this character? In your answer, specify in your phenotype descriptions the gender of the children. (For example, don’t just say 75% of the children would be colorblind – you would instead say 100 % of the daughters would be colorblind and 50% of the sons would be colorblind. Note that this is not a correct answer; it is just to give you an idea of how to explain the correct phenotypes of the cross.)___
- A man who is an achondroplastic dwarf with normal vision marries a color- blind woman of normal height. The man's father was 6 feet tall, and both the woman's parents were of average height. Achondroplastic dwarfism is autosomal dominant, and red-green color blindness is X-linked recessive. They have a daughter who is a dwarf with normal vision. What is the probability that she is heterozygous for both genes? а. 0% b. 25% c. 50% d. 75% е. 100%In fruit flies, normal wings (G) are dominant to glossy wings (g) and red eyes (R) are dominant to clear eyes (r). This trait is controlled by autosomal alleles. A male fly that is homozygous for normal wings and has clear eyes mates with a female fly that has glossy wings and is homozygous for red eyes. What is the expected phenotype ratio (in percent) of the F2 generation from this cross? Normal/Red: 18.75 6.25 9 56.25 Normal/Clear: 3 18.75 56.25 6.25 Glossy/Red: 56.25 6.25 3 18.75 Glossy/Clear: 56.25 1 6.25 18.75Consider a situation where you have a parental cross with the mother and father phenotypes listed below. Remember that the genotype for the wild-type parent is always homozygous. The counts of the F1 offspring are listed in Table 1. Two randomly selected individuals are selected and mated to produce a set of F2 individuals. If you test the F2 counts to determine whether they are consistent with an autosomal dominant mode of inheritance, what is your decision? Use a 0.05 significance level. PARENTAL CROSS Parental cross: Mother with disease phenotype, Father with wild-type phenotype. Table 1. F1 DATA Gender Phenotype Disease Wild-type Male 0 23 Female 0 34 Table 2. F2 DATA Gender Phenotype Disease Wild-type Male 7 25 Female 0 25 A)Do not reject the null hypothesis that the F2 data are consistent with an autosomal dominant mode of inheritance; chi-square goodness of fit test statistic value is between 0 and 1. B)Reject the null…