Consider the Fibonacci sequence F(0)=0, F(1)=1 and F(i)=F(i-1)+F(i-2) for i > 1. For the sake of this exercise we define the height of a tree as the maximum number of vertices of a root-to-leaf path. In particular, the height of the empty tree is zero, and the height of a tree with a single vertex is one. Prove that the number of nodes of an AVL tree of height h is at least F(h) and this inequality is tight only for two values of h.

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A: Given

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A: SUMMARY: - hence we got the output.

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A: Given:

Q: Sereja likes to hang around trees. A tree is an undirected graph on N vertices with N-1 edges and no…

A: Given:

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Q: Sereja likes to hang around trees. A tree is an undirected graph on N vertices with N-1 edges and no…

A: Given:

Q: Sereja likes to hang around trees. A tree is an undirected graph on N vertices with N-1 edges and no…

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A: The answer of the following is given below.

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A: Below is the answer to above question. I hope this will be helpful for you...

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A: solution of the given question is:-

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A: ANSWER:-

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A: Below is the answer to above question. I hope this will be helpful for you..

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A:

Minimum Spanning Tree

A spanning tree is a sub-graph of a connected, undirected graph. It has all the vertices of a graph with the minimum possible number of edges. If a vertex is skipped, then it will not be a spanning tree. The edges of a spanning tree may or may not have weights.