Consider the following problem. How much energy is evolved during the formation of 197 g of Fe, according to the reaction below? Fe203(s) + 2 Al(s)Al203(s) +2 Fe(s) AH°rxn -852 kJ 21. How do you find the correct answer to the problem question? ODH(rxn of 197 g of Fe) ratio of (#mol from 197g of Fe in reaction / 2 mol of Fe in equation) x DH(rxn of 2 mol of Fe). #mol from 197 g of is not known and should be determined next. O DH(rxn of 197 g of Fe) ratio of (2 mol of Fe in equation / #mol from 197g of Fe in reaction) x DH(rxn of 2 mol of Fe). #mol from 197 g of is not known and should be determined next. DH(rxn of 197 g of Fe) ratio of (#mol from 197g of Fe in reaction/ 2 mol of Fe in equation) / DH(rxn of 2 mol of Fe), #mol from 197 g of is not known and should be determined next.

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Consider the following problem.
How much energy is evolved during the formation of 197 g of Fe, according to the
reaction below?
Fe203(s) + 2 Al(s) - Al203(s) + 2 Fe(s) AH°rxn = -852 kJ
21. How do you find the correct answer to the problem question?
ODH(rxn of 197 g of Fe) = ratio of (#mol from 197g of Fe in reaction / 2 mol of Fe
in equation) x DH(rxn of 2 mol of Fe). #mol from 197 g of is not known and
should be determined next.
O DH(rxn of 197 g of Fe) = ratio of (2 mol of Fe in equation / #mol from 197g of Fe
in reaction) x DH(rxn of 2 mol of Fe). #mol from 197 g of is not known and
should be determined next.
DH(rxn of 197 g of Fe) = ratio of (#mol from 197g of Fe in reaction / 2 mol of Fe
in equation) / DH(rxn of 2 mol of Fe). #mol from 197 g of is not known and
should be determined next.
Transcribed Image Text:Consider the following problem. How much energy is evolved during the formation of 197 g of Fe, according to the reaction below? Fe203(s) + 2 Al(s) - Al203(s) + 2 Fe(s) AH°rxn = -852 kJ 21. How do you find the correct answer to the problem question? ODH(rxn of 197 g of Fe) = ratio of (#mol from 197g of Fe in reaction / 2 mol of Fe in equation) x DH(rxn of 2 mol of Fe). #mol from 197 g of is not known and should be determined next. O DH(rxn of 197 g of Fe) = ratio of (2 mol of Fe in equation / #mol from 197g of Fe in reaction) x DH(rxn of 2 mol of Fe). #mol from 197 g of is not known and should be determined next. DH(rxn of 197 g of Fe) = ratio of (#mol from 197g of Fe in reaction / 2 mol of Fe in equation) / DH(rxn of 2 mol of Fe). #mol from 197 g of is not known and should be determined next.
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