Consider the following reaction: N2(g) + 3H2(g) ⇌ 2NH3(g) In a given experiment, 1.21 moles of N2(g) and 4.01 moles of H2(g) were placed in a 4.63 L vessel. Complete the following table by entering numerical values in the Initial row and values containing the variable "x" in the Change and Equilibrium rows. Define x as the amount (mol/L) of N2 that reacts to reach equilibrium. Include signs in the Change column to indicate a gain or loss of concentration. (Omit units and spaces, use 3 sig. fig. and write concentration less than 1 as 0.###, not as .###. If nothing is present initially, enter 0 for the molarity.)   [N2] (M) [H2] (M) [NH3] (M) Initial       Change       Equilibrium       At a particular temperature, the equilibrium concentration of NH3 is found to be 0.279 M. Given this information, determine the numerical value of K for this reaction, at this temperature. (If you want to enter your answer in scientific notation, use the format as shown below: 2.5 x 10-3 = 2.5E-3)

Chemistry for Engineering Students
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Chapter12: Chemical Equilibrium
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Consider the following reaction:

N2(g) + 3H2(g) ⇌ 2NH3(g)

In a given experiment, 1.21 moles of N2(g) and 4.01 moles of H2(g) were placed in a 4.63 L vessel. Complete the following table by entering numerical values in the Initial row and values containing the variable "x" in the Change and Equilibrium rows. Define x as the amount (mol/L) of N2 that reacts to reach equilibrium. Include signs in the Change column to indicate a gain or loss of concentration. (Omit units and spaces, use 3 sig. fig. and write concentration less than 1 as 0.###, not as .###. If nothing is present initially, enter 0 for the molarity.)


  [N2] (M) [H2] (M) [NH3] (M)
Initial      
Change      
Equilibrium      

At a particular temperature, the equilibrium concentration of NH3 is found to be 0.279 M.

Given this information, determine the numerical value of K for this reaction, at this temperature.
(If you want to enter your answer in scientific notation, use the format as shown below:
2.5 x 10-3 = 2.5E-3)

K = 

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