Consider the reaction PO + DONG → PODONG, determine the reaction order for each component and the rate constant. The reaction rates of various PODONG formations are given below. Runs [PO], M [DONG], M Rate, x 104 M/s 1 0.40 1.20 1.97 2 0.80 1.20 7.89 3 0.40 0.40 0.073 4 1.20 0.80 5.23
Consider the reaction PO + DONG → PODONG, determine the reaction order for each component and the rate constant. The reaction rates of various PODONG formations are given below. Runs [PO], M [DONG], M Rate, x 104 M/s 1 0.40 1.20 1.97 2 0.80 1.20 7.89 3 0.40 0.40 0.073 4 1.20 0.80 5.23
Introduction to General, Organic and Biochemistry
11th Edition
ISBN:9781285869759
Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Publisher:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Chapter7: Reaction Rates And Chemical Equilibrium
Section: Chapter Questions
Problem 7.18P
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![Consider the reaction PO + DONG → PODONG, determine the reaction order for each
component and the rate constant. The reaction rates of various PODONG formations are given
below.
Runs
[PO], M
[DONG], M
Rate, x 104 M/s
1
0.40
1.20
1.97
2
0.80
1.20
7.89
3
0.40
0.40
0.073
4
1.20
0.80
5.23](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3cfa2856-f0ff-433a-9574-47c58c2b6818%2F687e5a79-66b7-42dd-af5d-3fe7c04244a6%2Fq039mq9_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Consider the reaction PO + DONG → PODONG, determine the reaction order for each
component and the rate constant. The reaction rates of various PODONG formations are given
below.
Runs
[PO], M
[DONG], M
Rate, x 104 M/s
1
0.40
1.20
1.97
2
0.80
1.20
7.89
3
0.40
0.40
0.073
4
1.20
0.80
5.23
![e. Given initial
concentrations of
[PO]= 0.439M and [DONG]= 0.567, how
much time (s) is needed to form 0.324M
of [PODONG].](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3cfa2856-f0ff-433a-9574-47c58c2b6818%2F687e5a79-66b7-42dd-af5d-3fe7c04244a6%2F5s3nu9k_processed.jpeg&w=3840&q=75)
Transcribed Image Text:e. Given initial
concentrations of
[PO]= 0.439M and [DONG]= 0.567, how
much time (s) is needed to form 0.324M
of [PODONG].
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