create a piece of code that demonstrates how to find a key K using a skip list S. The search is carried out using the algorithm using the functions next(p) and below(p).
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create a piece of code that demonstrates how to find a key K using a skip list S. The search is carried out using the
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- Q2: a. Write an algorithm that searches a sorted list of n items by dividing it into three sublists of almost n/3 items. This algorithm finds the sublist that might contain the given item and divides it into three smaller sublists of almost equal size. The algorithm repeats this process until it finds the item or concludes that the item is not in the list. Dry run the above algorithm to find the value 240. A[] = {10,15,20,60,65,110,150,220,240,245,260,290,300,460,470,501}This chapter's bubble sort method is less efficient than it could be. If a pass through the list is done without swapping any components, the list is sorted and there is no reason to continue. Change this algorithm to terminate as soon as it recognises that the list is sorted. A break statement should not be used.This chapter's bubble sort method is less efficient than it could be. If a pass through the list is done without swapping any components, the list is sorted and there is no reason to continue. Change this algorithm to terminate as soon as it recognises that the list is sorted. A break statement should not be used.This chapter's bubble sort method is less efficient than it could be. If a pass through the list is done without swapping any components, the list is sorted and there is no reason to continue. Change this algorithm to terminate as soon as it recognises that the list is sorted. A break statement should not be used.This chapter's bubble sort method is less efficient…The function interleave_lists in python takes two parameters, L1 and L2, both lists. Notice that the lists may have different lengths. The function accumulates a new list by appending alternating items from L1 and L2 until one list has been exhausted. The remaining items from the other list are then appended to the end of the new list, and the new list is returned. For example, if L1 = ["hop", "skip", "jump", "rest"] and L2 = ["up", "down"], then the function would return the list: ["hop", "up", "skip", "down", "jump", "rest"]. HINT: Python has a built-in function min() which is helpful here. Initialize accumulator variable newlist to be an empty list Set min_length = min(len(L1), len(L2)), the smaller of the two list lengths Use a for loop to iterate k over range(min_length) to do the first part of this function's work. On each iteration, append to newlist the item from index k in L1, and then append the item from index k in L2 (two appends on each iteration). AFTER the loop…
- Split - Filter - Sort romeo = 'But soft what light through yonder window breaks It is the east and Juliet is the sun Arise fair sun and kill the envious moon Who is already sick and pale with grief Split the long string romeo into a list of words using the split function. For each word, check to see if the word is already in a list. If the word is not in the list, add it to the list. When the program completes, sort and print the resulting words in alphabetical order. The result will be like this: ['Arise', 'But', 'It', 'Juliet', "Who', 'already', 'and', 'breaks', 'east', 'envious', 'fair', 'grief', 'is', 'kill', "'ight', 'moon', 'pale', 'sick', 'soft', 'sun', 'the', 'through', 'what', 'window', 'with', 'yonder']python help Q7: No Repeats Implement no-repeats, which takes a list of numbers s as input and returns a list that has all of the unique elements of s in the order that they first appear, but no repeats. For example, (no-repeats (list 5 4 5 4 2 2)) evaluates to (5 4 2). Hints: To test if two numbers are equal, use the = procedure. To test if two numbers are not equal, use the not procedure in combination with =. You may find it helpful to use the filter procedure. (define (no-repeats s) 'YOUR-CODE-HERE ) ;;; Tests (no-repeats (list 5 4 5 4 2 2)) ; expect (5 4 2) Q8: Substitute Write a procedure substitute that takes three arguments: a list s, an old word, and a new word. It returns a list with the elements of s, but with every occurrence of old replaced by new, even within sub-lists. Hint: The built-in pair? predicate returns True if its argument is a cons pair. Hint: The = operator will only let you compare numbers, but using equal? or eq? will let you compare symbols as…def eliminate_neighbours (items): Given the sequence of integer items that are guaranteed to be some permutation of positive integers from 1 to n where n is the length of the list, find the smallest number among those that still remain in the list, and remove from the list both that number and whichever of its current immediate neighbours is larger. The function should repeat this basic operation until the largest number in the original list gets eliminated. Return the number of removal operations that were needed to achieve this goal. For example, given the list [5, 2, 1, 4, 6, 31, the operation would remove element 1 and its current larger neighbour 4, resulting in the list [5, 2, 6, 3]. Applied again, that operation would remove 2 and its current larger neighbour 6, thus reaching the goal in two steps. items Expected result [1, 6, 4, 2, 5, 3] 1 [8, 3, 4, 1, 7, 2, 6, 5] 3 [8, 5, 3, 1, 7, 2, 6, 4] 4 [1, 2, 3, 4, 5, 6, 7, 8, 9, 10] 5 range (1, 10001) 5000 [1000] + list(range (1, 1000))…
- Create a Flowchart for this code. import random #Define a function to pick 5 numbers from 1 to 38 def getNJCash5lottery_numbers(): #Return the list return random.sample(range(1, 39), 5) def playNJCash5lottery(): #Call the method and assign the list to variable lottery_number = getNJCash5lottery_numbers() print("These are the cash 5 numbers."), #Iterate over list elements for number in lottery_number: #Print the number on one line print(number) #Define a function def main(): while(True): #Call the method to print the list elements playNJCash5lottery() #Prompt the user if they want to play again decide = input("\nDo you want to play again? Yes/No : ") #If they entered "no " or "No" if decide.lower() == "no": #Exit break #Call the "main()" function if __name__ == "__main__": main()scheme: Q7: No Repeats Implement no-repeats, which takes a list of numbers s as input and returns a list that has all of the unique elements of s in the order that they first appear, but no repeats. For example, (no-repeats (list 5 4 5 4 2 2)) evaluates to (5 4 2). Hints: To test if two numbers are equal, use the = procedure. To test if two numbers are not equal, use the not procedure in combination with =. You may find it helpful to use the filter procedure. (define (no-repeats s) 'YOUR-CODE-HERE ) ;;; Tests (no-repeats (list 5 4 5 4 2 2)) ; expect (5 4 2)Describe how to perform a sequential search on a list.
- The function that will a single items to the list is Oextend (...) Oadd(...) Oappend(...) Olengthen(...)There are 26 students in COMP 3140 class. Generate a list of lists named L. Each list in L contains 5 random grades (60-100), representing the grades of 5 assignments of a student. Using Python high order function – Mapping, compute the average grade for each student.write a function that add any item in a linked list after the item X, if the item X is not found in the linked list don't add the item. data structre please solve it fast less than 30 minute