CS 2( g) + 3Cl 2( g) <=> CCl 4( g) + S 2Cl 2( g)At a given temperature, the reaction above is at equilibrium when [CS2] = 0.075 M, [Cl2] = 0.35 M, [CCl4] = 0.25 M, and [S2Cl2] = 0.45 M. What will be the direction of the reaction when the reactants and products have the following concentrations: CS2 = 0.15 M, Cl2 = 0.15 M, CCl4 = 0.45M, and S2Cl2 = 0.31 M?I would like help with this problem I am solving for Kc and then Qc I believe.for Kc I set up the following equation using the molarity values in the brackets as (.25)(.45)/(.075)(.035)^3 and the Qc as (.45)(.31)/(.15)(.15)^3

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Answered: CS 2( g) + 3Cl 2( g) <=> CCl 4( g) + S…

Chemistry: An Atoms First Approach

2nd Edition

ISBN:9781305079243

Author:Steven S. Zumdahl, Susan A. Zumdahl

Publisher:Steven S. Zumdahl, Susan A. Zumdahl

Chapter12: Chemical Equilibrium

Section: Chapter Questions

Problem 3RQ

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CS ₂( g) + 3Cl ₂( g) <=> CCl ₄( g) + S ₂Cl ₂( g)

At a given temperature, the reaction above is at equilibrium when [CS₂] = 0.075 M, [Cl₂] = 0.35 M, [CCl₄] = 0.25 M, and [S₂Cl₂] = 0.45 M. What will be the direction of the reaction when the reactants and products have the following concentrations: CS₂ = 0.15 M, Cl₂ = 0.15 M, CCl₄ = 0.45M, and S₂Cl₂ = 0.31 M?

I would like help with this problem I am solving for Kc and then Qc I believe.

for Kc I set up the following equation using the molarity values in the brackets as (.25)(.45)/(.075)(.035)^3 and the Qc as (.45)(.31)/(.15)(.15)^3

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