Current 450 Problems 9.8 A three phase Ihe be tween phase conductors of 4 m. Each con ductor has has Legui latesal) spacing with separa bon d's tance radius of 1.5cm. a De tesmine: a) The inductance ger phase in mH Jmi I'= (1.5x10-2) en Inductance res phase of 3ø = 2x10-7 In GMD -1/4 > 0. 011 68 M GMD= (43)"B = 4, La= 2x107 In - 1.167 X106H)m 0.o1 68 (). 16 7 x 10-* Cwim] x 1o* = I.167x l0[mtH/m] (1. 167 x10[m H /m]) *lo00 - 1.167 mH/ km (1.167 mH /km) x 1.6 1. 8672 mH /me The inductance per phuse is | 1.8672 mH/mi ) The Sinduc t.ve reactance per phase in r /km and Do I need GMB (geometric mean radius) to solve ?
Current 450 Problems 9.8 A three phase Ihe be tween phase conductors of 4 m. Each con ductor has has Legui latesal) spacing with separa bon d's tance radius of 1.5cm. a De tesmine: a) The inductance ger phase in mH Jmi I'= (1.5x10-2) en Inductance res phase of 3ø = 2x10-7 In GMD -1/4 > 0. 011 68 M GMD= (43)"B = 4, La= 2x107 In - 1.167 X106H)m 0.o1 68 (). 16 7 x 10-* Cwim] x 1o* = I.167x l0[mtH/m] (1. 167 x10[m H /m]) *lo00 - 1.167 mH/ km (1.167 mH /km) x 1.6 1. 8672 mH /me The inductance per phuse is | 1.8672 mH/mi ) The Sinduc t.ve reactance per phase in r /km and Do I need GMB (geometric mean radius) to solve ?
Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN:9781305632134
Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Chapter2: Fundamentals
Section: Chapter Questions
Problem 2.6MCQ
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I need help to find the inductive reactance per phase in the following 3 phase line problem. I just need help with part b of the question.
![Current 450 Problems
has Lequilatesal spacing
9.8 A three phase line
be tween phase conductors with
of 4 M. Fach
separa ton di's tance
radus of 1.5cm.
con ductor has
a
De termine:
a) The inductance ger phase in mH Imi
-1/4
s'= (1.5x102)e" > 0. o 11 68m
Inductance rer phase of 3ø = 2x10-7 In GMD
GMD= (43)"B = 4, La= 2x107 In
1,167 x106H/m
0.0U 68
().167 x 10 * [wim3) x lo* = 167y lo[nH/m]
(1. 167 x10:$ [m H/m])) ×lo00 - 1.167 mH/km
(1.167 mH /km) x 1-6= 1, 8672 mA /mb
The inductance per phuse is 1.8672 mH/mi
) The Sinduc t.ve reactance
per phase
in /km and
/mi
Do I need GMR (geometric
mean radius) to solve ?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5362cbea-9427-4b2b-99cb-57a208edd853%2F57b14770-160d-4af1-b6a6-a17829f514c7%2F3bk5zym_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Current 450 Problems
has Lequilatesal spacing
9.8 A three phase line
be tween phase conductors with
of 4 M. Fach
separa ton di's tance
radus of 1.5cm.
con ductor has
a
De termine:
a) The inductance ger phase in mH Imi
-1/4
s'= (1.5x102)e" > 0. o 11 68m
Inductance rer phase of 3ø = 2x10-7 In GMD
GMD= (43)"B = 4, La= 2x107 In
1,167 x106H/m
0.0U 68
().167 x 10 * [wim3) x lo* = 167y lo[nH/m]
(1. 167 x10:$ [m H/m])) ×lo00 - 1.167 mH/km
(1.167 mH /km) x 1-6= 1, 8672 mA /mb
The inductance per phuse is 1.8672 mH/mi
) The Sinduc t.ve reactance
per phase
in /km and
/mi
Do I need GMR (geometric
mean radius) to solve ?
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