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- The stresses on an element are sx= 1000 Psi. sy= 500 psi, and txy= 350 psi. Find the stresses acting on an element oriented at an angle 0 = 250. Show these stresses on the rotated element.A brass plate with a modulus of elastici ty E = 16 X 106 psi and Poisson’s ratio a = 0.34 is loaded in biaxial stress by normal stresses r and cry. (sec figure). A strain gage is bonded to the plate at an angle 4 = 350 If the stress o is 10,700 psi and the strain means used by the gageise = 390 X 106.whatisthcmax- imum in-plane shear stress (Tr, ),. and shear strain (>‘ ).? What is the maximum shear strain (y ) in the x-: plane? What is the maximum shear strain (y ).. in the y-r plane?Solve the preceding problem if F =90 mm, F = 42 kN, and t = 40°MPa
- A simply supported beam is subjected to point load P at mid-span. The normal stress on an element at mid-span is known to be ??x= 1.5 ksi. Determine the element stresses lilt is rotated through angle ? = 450• Show these stresses on a sketch of an element oriented at that angle.A copper rod of length L = 18.0 in. is to be twisted by torques T (see figure) until the angle of rotation between the ends of the rod is 3.0°. (a) If the allowable shear strain in the copper is 0.0006 rad, what is the maximum permissible diameter of the rod? (b) If the rod diameter is 0.5 in., what is the minimum permissible length of the rod?Repeat the previous problem using ? = 50° and stresses on the rotated element: sy1= 70 MPa, ??y1=-82 MPa, and tx1y1=-35 MPa.
- .4 The stresses on an clement arc known to be sx= 120 MPa, sy= 100 MPa, and txy= 75 MPa. Find the stresses on an inclined section through the element at an angle ? = 45°.An element of aluminum is subjected to tri-axial stresses. Calculate the strains in the element in x, y, and z directions lithe stresses axayand az are -2000 psi, 3500 psi, and 2700 psi, respectively. Assume E = 10,000 ksi and v = 0.33. Also, find the unit volume change of the element.A spherical balloon is filled with a gas. The outer diameter of the balloon is 20 in. and the thickness is 0,012 in. Calculate the maximum permissible pressure in the balloon if the allowable tensile stress and the allowable shear stress in the balloon are 1 ksi and 0.3 ksi, respectively.
- A steel riser pipe hangs from a drill rig located offshore in deep water (see figure). (a) What is the greatest length (meters) it can have without breaking if the pipe is suspended in the air and the ultimate strength (or breaking strength) is 550 MPa? (b) If the same riser pipe hangs from a drill rig at sea, what is the greatest length? (Obtain the weight densities of steel and sea water from Table M, Appendix I. Neglect the effect of buoyant foam casings on the pipe.)Find the stresses in each direction, also find the change in volume of the block of dimension 120 mm x 60 mm x 43 mm, subjected to 3 mutually perpendicular loads. The load along length, breadth and depth directions are 10 kN (tensile), 25 kN (tensile), 13 kN (compressive) respectively, Take E as 180 GPa, Poisson's ratio as 0.3. The stress along length direction (Unit in kN/m2)= _____________ The stress along width direction (Unit in kN/m2)= _____________ The compressive stress along depth direction (Unit in kN/m2)= _____________ The change in volume of the block is (unit in mm3) = ______________Thank you for answering this question. Please you specify each step as soon as possible. Good Luck! Thank You. For a 60° angle lamina that subjected loads shown below, 15 MPa T 3.5 MPa 1.4 MPa Ox = -3.5 MPa, oy = 15 MPa, Txy = -1.4 MPa Calculate the stresses in L-T directions (ơ1, ơr, TLt) Determine whether the lamina will fail under these applied loads by using Tsai-Hill failure criteria. Determine whether the lamina will fail under these applied loads by using maximum stress failure criteria. Mechanical properties: EL = 14 GPa; ET=3.5 GPA; GLT = 4.2 GPa; vt = 0.40 Strength (In case of tension): OLU = 250 MPa, ơTu = 10 MPa Strength (In case of compression): OLU = 200 MPa, ơTu = 0.5 MPa Shear strength: TLTU = 8 MPa OT + OLu + <1 Tsai-Hill criterion: OLu - OLu