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- Solid copper(II) chloride forms a hydrate of formula CuCl2 ⋅ xH2O. A student heated a sample of hydrated copper(II) chloride, in order to determine the value of x. The following results were obtained: mass of crucible = 16.221 g mass of crucible and hydrated copper(II) chloride = 18.360 g mass of crucible and anhydrous copper(II) chloride = 17.917 g At. Mass: Cu 63.55 Cl 35.45 H 1.008 O 16.00 1. Calculate the number of moles of anhydrous copper(II) chloride (answer must be expressed to 5 decimal places)Solid copper(II) chloride forms a hydrate of formula CuCl2 ⋅ xH2O. A student heated a sample of hydrated copper(II) chloride, in order to determine the value of x. The following results were obtained: mass of crucible = 16.221 g mass of crucible and hydrated copper(II) chloride = 18.360 g mass of crucible and anhydrous copper(II) chloride = 17.917 g At. Mass: Cu 63.55 Cl 35.45 H 1.008 O 16.00 1. Calculate the number of moles of H2O (answer must be expressed to 5 decimal places)Solid copper(II) chloride forms a hydrate of formula CuCl2 ⋅ xH2O. A student heated a sample of hydrated copper(II) chloride, in order to determine the value of x. The following results were obtained: mass of crucible = 16.221 g mass of crucible and hydrated copper(II) chloride = 18.360 g mass of crucible and anhydrous copper(II) chloride = 17.917 g At. Mass: Cu 63.55 Cl 35.45 H 1.008 O 16.00 1. Calculate percentage of H2O (answer must have 4 sig. fig)
- Solid copper(II) chloride forms a hydrate of formula CuCl2 ⋅ xH2O. A student heated a sample of hydrated copper(II) chloride, in order to determine the value of x. The following results were obtained: mass of crucible = 16.221 g mass of crucible and hydrated copper(II) chloride = 18.360 g mass of crucible and anhydrous copper(II) chloride = 17.917 g At. Mass: Cu 63.55 Cl 35.45 H 1.008 O 16.00 1. Calculate percentage of anhydrous copper(II) chloride (answer must have 4 sig. fig)Use the References to access important values if needed for this question. Two-Step Algebra a =b+ cd lne In order to solve the equation above for d, you must: Step One Add the same expression to each side of the equation to leave the term that includes the variable by itself on the right-hand side of the expression: -b ta =-bv +b+ cd Ine Step Two Multiply both sides of the equation by the same expression: x(a - b) = xcd Ine The resulting equation is: d = SubmitIn a hydrochloric acid (HCl) molecule, the distance between the hydrogen atom and the chlorine atom is 1.27 × 10-10 meters. The mass of an hydrogen atom is 2 atomic mass units (amu) and the mass of a chlorine atom is 35 amu. How far from the hydrogen (H) atom is the center of mass of the molecule, in meters? Justify your answer using your equations and rationale used.
- Q1-Complete the blanks? -Major categories of gaseous atmospheric chemical species are................. -An atmospheric molecule designated by an asterisk, such as NO2*, is ............... -An atmospheric species designated with a dot, such as HO., is a .............. possessing an...........................You and your friends are having lunch together and complaining about the cold weather. Kathy begins telling about her spring break trip to warm, sunny Spain. She starts to laugh when she tells the group that she was frustrated when she awoke on the first day to an outside temperature of 18° and a predicted high of 24°. Kathy was laughing because in Spain temperatures are measured in Celsius. What was the predicted high in Fahrenheit? > View Available Hint(s) O75.2 °F 6.2 °F 100.8 °F O75 °FYou have two distinct gaseous compounds made from element X and element Y. The mass percents are as follows: Compound I: 30.43% X, 69.57% Y Compound II: 63.64% X, 36.36% Y In their natural standard states, element X and element Y exist as gases. (Monatomic? Diatomic? Triatomic? That is for you to determine.) When you react gas X with gas Y to make the products, you get the following data (all at the same pressure and temperature): 1. volume gas X + 2 volumes gas Y2 volumes compound I 2. volumes gas X + 1 volume gas Y2 volumes compound II Assume the simplest possible formulas for reactants and products in the chemical equations above. Then, determine the relative atomic masses of element X and element Y.
- Marie Curie was born in Poland but studied and carried out her research in Paris. In 1903, she shared the Nobel Prize in Physics with H. Becquerel and her husband Pierre for their discovery of radioactivity. (In 1911 she received the Nobel Prize in Chemistry for the discovery of two new chemical elements, radium and polonium, the latter named for her homeland, Poland.) They and others observed that a radioactive substance could emit three types of radiation: alpha (), beta (), and gamma (). If the radiation from a radioactive source is passed between electrically charged plates, some particles are attached to the positive plate, some to the negative plate, and others feel no attraction. Which particles are positively charged, which are negatively charged, and which have no charge? Of the two charged particles, which has the most mass? Radioactivity. Alpha (), beta I(), and gamma () rays from a radioactive element are separated by passing them between electrically charged plates.Choose the correct answer choice. Given the statement below, which choice best accounts for these observations?9) An experiment was done in which zinc was reacted with hydrochloric acid in a vessel to make hydrogen gas and zinc chloride. After heating off everything in the dish except the remaining solid zinc chloride, this data was considered: Mass of empty evaporating dish: 113.5 g Mass of evaporating dish + zinc (before the reaction): 116.0 g Mass of evaporating dish + zinc chloride (at end of exp't): 118.8 g Given the following lab data, what is the empirical formula of zinc chloride? A) ZnCI B) Zn4CI C) Zn2Cl D) ZnCl2 E) Zn2Cl4