Describe the tangent line at an arbitrary point on the graph of y = 2x + 8

Q: Find the slope of the tangent line to the graph of y = √x − 1 at the point (5,2).

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Q: Find the equation of the tangent line to the graph of x4 y2 = 144 at the point (2, 3) and at the…

A: Equation of the tangent line to the graph of x4y2=144 at the point (2, 3) Now, differentiate the…

Q: Find an equation of the line tangent to the graph of y = exat x = 0.

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Q: Find an equation of the tangent line to the graph of the function at the given point. y = 4-x- In(x+…

A: The function is given by y = 4-x2-ln12x+1 The point is x0,y0 = 0,4 To evaluate the equation of the…

Q: Find the slope of the tangent to the curve y = 3 + 4x² – 2x' at the point where x=a. Draw the graph…

A: Slope of the tangent is derivative of the function .

Q: find the slope of the tangent line to the graph of flx)= 2x at (5,3).

A: NOTE: Refresh your page if you can't see any equations. . to find the slope of the line, take the…

Q: Write the equation of the tangent line to the curve y = x3 + 3x - 8 at (2, 6).

A: To find the equation of the tangent line to the curve y=x3+3x-8 at (2,6). Solution: We know, The…

Q: Find the equation of the tangent line to the graph of y = 2x +- at the point (1,5).

A: We have given

Q: Find the slope of the tangent line to the graph of y = x2 where x = -.2.

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Q: Find all the points on the graph of (x² + y²)² = x² – y² that have horizontal tangent line.

A: Hello. Since your question has multiple parts, we will solve first question for you. If you want…

Q: Find the equation for the tangent line of the graph of 4 y = x² at (-2, 16). Equation:

A: Here we have to find the equation of the tangent line of the graph y=x4 at (-2, 16)

Q: Find an equation of the tangent line to the graph of the function at the given point.

A: the given function is y=2-x. so to find the tangent at a specified point given (-1 , 2 ). it is…

Q: Find the equation of the tangent line to the curve y=5x³-1 at x= -1.

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Q: Find the equation of the tangent line at the given point on curve.

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Q: The slope of the tangent line to the curve y=2eUXcos(-6x) at x-0 is

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Q: Find an eqaution of the tangent line to the curve at the given point. y = 4x - 3x2, (2,-4)

A: The given function is y=4x-3x2 and the point is 2,-4

Q: Find the equation of the tangent line to the graph of ƒ(x) = 4/x at x = 2

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Q: Explain how to write an equation of the tangent line to the graph of f(x) = x2 at (2, 4).

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Q: Find equation of the tangent line to the graph of y=sqrt(x^3-2) At the point where x=3

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Q: Find the equation of the tangent line to the graph of y = 2x - (4 / √x) at the point (4, 6).

A: Given,            y = 2x - 4x and Point is 4, 6

Q: Write the equation of the tangent line to the curve = 2 at the point (1,1). .3

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Q: Find an equation of the tangent line to the graph of y = 2x/x2+1 at the origin and at the point…

A: use differentiation for finding the slope and then use slope intercept form for finding the tangent…

Q: Find an equation of the tangent line to the curve at the given point. y = 2x3 – x2 + 4, (2,16) y =

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Q: Find the slope of the tangent line at given point 2x2 - 3y = x at (1.5,1)

A: First derivative of the equation curve give slope of tangent line to the curve.

Q: Find the equation of the tangent line to the curve y=(x-2) (x+1)? at point (3, 16).

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Q: Find one point on the curve where the tangent line is horizontal y2=x3-3x

A: We have the equation of given curve as y2=x3-3x Now, the slope of the tangent can be calculated as…

Q: Find the slope of the tangent line to the graph at the given point. (x2 + 4)y = 8, (-2, 1)

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Q: Find the slope of the tangent line to the curve 4x + lay- ly = 88 at the point (3, - 4).

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Q: Determine the equation of the curve at every point of which the tangent line has a slope of 2x.

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Q: Find an equation for the tangent line to the curve n = 4- 2 at (-1,3).

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Q: Find the points on the graph of y = ex where the tangent line has slope 4.

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Q: Find all the points on the graph of (x² + y²)² = x² – y² that have vertical tangent line.

A: This question is taken from the tangent and line in which we have to all points on the graph that…

Q: Find the slope of the tangent line to the graph at the given point. 4xcosy +1 = 5 at the point (2,)

A: Solve, as follows: 4xcosy+1=541cosy+x-sinydydx=0dydx=cosyxsiny

Q: Write an equation of the tangent line to the curve x2+y2-25=0 at the point (3,4).

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Q: Find an equation of the tangent line to the curve at the given point y = 2x3 - x2 + 5, (2, 17) y =

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Q: find an equation for the tangent line to the graph of y=(5-2x)^2 at (3,1).

A: Explanation of the answer is as follows

Q: What is the slope of the tangent line to the graph of y-(x-1)/(x+1) at x-1?

A: We have to find

Q: Find the point(s) on the graph of y = (x2 - 143)eX where the tangent line is horizontal.

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Q: Find an equation of the tangent line to the curve at the given point. y = 2x2 - 6x + 1, (4, 9) y =

A: First find slope at given value then equation of tangent line

Q: Find an equation of the tangent line to the graph of y = e at the point 5,

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Q: What is the slope of the tangent line to the graph of y-(x-1)/(x+1) at x-3?

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Q: Find an equation of the tangent line to the graph of y = x³ - 3x - 1 at the point (2, 1).

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Q: Write the equation of the tangent line to the graph of y = x at the point x = - 0.7.

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Q: What is the slope of the tangent line that touches the graph of In(y) + eA-=3y-4x at the point 3. 5

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Q: Find the equation of the tangent line to the curve y = (1 + 2x)² at the point (4, 81). ソ=

A: First find the slope of the tangent line with the help of derivative of the given curve than write…

Q: find an equation of the tangent line that passes through y=x^3+x+4 at (-(2,-6)

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Q: Find the exact value of the slope of the tangent line to the graph of −3x2+xy+4y3=102at the point…

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Q: Determine the slope of the tangent line to the graph of ƒ (x) =- at the point(4, -4).

A: Use differentiation for finding the slope.

Q: Find an equation of the tangent line to the graph of y = arcsin(2x) at the point 2/2 4

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Q: Find an equation of the tangent line to the curve at the given point. y = 2x³x² + 2, (1, 3) y = 6x²…

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