- Design a square tied column to support an axial dead load D of 130 kips and an axial live load L of 180 kips. Initially assume that 2% longitudinal steel is desired, fc' = 4000 psi, and fy = 60,000 psi.
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- A concrete circular column with a radius of 350mm has f'c-25 MPa and is braced against sidesway. The column is assumed to be pinned on both ends with an unsupported length is 6.1meters. The column is subjected to the following service loads: Axial Dead Load =350 kN Axial Live Load=480 kN Moment due to Dead Load on the top of the column = 125 kN-m Moment due to Dead Load on the bottom of the column = 60 kN-m Moment due to Live Load on the top of the column = 122 kN-m Moment due to Live Load on the bottom of the column = 75 kN-m. If the moments bent the column in a singular curve, determine the following: 1. Critical Load on the column, kN 2. Moment Magnifying factor 3. Design Moment of the column, kN-m.The structural system below using rotational spring + hinge support at joint A and rotational spring + hinge connector at joint B. A horizonal load Q acts at joint C. Please find the critical load Qer. 2k B LA. Design an axially loaded short square tied column for Pu = 2600 KN if fc' = 28 MPa and fy = 350 MPa. Initially assume p = 0.02. Sketch the column cross-section and rebar arrangement. Use NSCP 2015 standard
- ! Required information A 20-mm-diameter rod made of the same material as rods AC and AD in the truss shown was tested to failure and an ultimate load of 150 kN was recorded. Use a factor of safety of 3.0. 1.5 m D В 3 m 3 m 48 kN 48 kN Determine the required diameter of rod AC. The required diameter of rod AC is 31.48 mm.Use "Unit Load method" & Mueller-Breslau Principle Please Influence Lines for: MA VA MB VB 0.5L 0.5La) The floor system shown is subjected to a total uniform distributed load of 12 KN/m². Sketch the loading that acts along the members DE and BDG. -2.0 m - 3.0 m- A 3.0 m D E 5.0 m F G
- c) The three suspender bars are made of A-36 steel and have equal cross-sectional areas of 450 mm² .Determine the average normal stress in each bar if the rigid beam is subjected to the loading shown. A B C 80 kN 2 m 50 kN D E F -1m--1m--1 m--1m-|PROBLEM 2: The steel beam loaded below has the built-up cross section as shown. Determine the maximum permissible value of the load w so as not to exceed allowable bending stresses of 110 MPa. -125 mm- w (including beam weight) 20 mm 20 mm 100 mm .-- NA A B - 2 m - 6 m 20 mm FINAL ANSWER: Max. allowable w kN/mQz- Find the, Critical load Pe using E=2x1ổ Pc Pery 4m
- Design an angle iron purlin for a roof having a slope of 26° with the horizontal. . The trusses are spaced at 4 m c/c. The purlin carries dead load of 4.0 kN/m and wind load 1.5 kN/m normal to the roof surface. Use IS: 800 specifications. Adopt Fb = 142 MPa for vertical loads and 177.5 MPa for vertical and wind loads combined. %3DA steel pipe has an inside diameter of 196mm and an outside diameter of 206mm. It has an unsupported height of 3.5m. Using A36 steel with Fy = 248 MPa and E = 200,000 MPa. Compute the allowable axial load Pa (ASD) and ultimate axial load Pu (LRFD) that the column could carry: a. if bottom end is fixed and top end is rotation free and translation free. b. if both ends are pinned & unsupported height = 5 meters Properties of steel pipe: A = 3157.3 mm? |= 15.954 × 106 mm4 r= 71.09 mm4 -800mm- 2-20mm DIA A 3-32mm DIA od قت -300mm 4 D 90mm 450mm