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- Shown above is a family pedigree tree in which family members afflictedwith the disease Haemophilia are shown with filled-in squares (male) or circles (females). A couple is trying to determine the likelihood of passingon the disease to their future children (represented by the ? symbolabove) because the hemophilia runs in the woman’s family. Turner syndrome is a disease in which an individual is bornwith only a single X chromosome. Suppose the woman in thecouple is a carrier for hemophilia and has a child with Turnersyndrome. Would this child have the disease?A woman who sought genetic counseling is found to be heterozygousfor a chromosomal rearrangement between the second andthird chromosomes. Her chromosomes, compared to those in anormal karyotype, are diagrammed on the next page:(a) This woman is phenotypically normal. Does thissurprise you? Why or why not? Under what circumstancesmight you expect a phenotypic effect of such arearrangement?If a man with dark skin whose genotype is AaBB reproduces with a woman who has light skin (aaBb), what are the possible skin colors that their children will have? Develop a Punnett square and list the possible genotypes & phenotypes. For your convenience, a table is presented below that shows several possible genotypes & phenotypes: Genotypes Phenotypes AABB Very dark skin AABb or AaBB Dark skin AaBb, AAbb, or aaBB Medium brown skin Aabb or aaBb Light skin aabb Very light skin
- Please answer all of them, they are all connected. PEDIGREE ANALYSIS and SYMBOLOGY: Examine the pedigree which has X linked Dominant inheritance of disorder. Use letter X* (asterisk denotes disorder) as genotype of the individuals which can be XX, XY, X*X*, X*X and X*Y. a. What is the genotype of IV-6? b. What is the genotype of III-6? c. What is the genotype of II-3? d. What is the genotype of III-8? e. If couple I-1 and I-2 will have a son, what is the probability of having the disorder? f. If couple III-8 and III-9 will have another child, what is the probability of having the disorder? g. Theoretically, if individual IV-3 and individual IV-5 will marry and will have a child, what is the probability of having a child without the X-linked disorder?Two people are planning to have children together. Each person is heterozygous for the gene “A”. Using this letter, first list all the possible gametes that the two people can produce. Next, write all the possible genotypes and phenotypes for their offspring, using the correct genetic terminology (e.g., “genotype is homozygous dominant” “phenotype is dominant”). HINT: Use the gametes to construct a Punnett square and predict the possible offspring (you do not need to include the Punnett square in your answer).A woman who sought genetic counseling is found to be heterozygousfor a chromosomal rearrangement between the second andthird chromosomes. Her chromosomes, compared to those in anormal karyotype, are diagrammed on the next page:(a) What kind of chromosomal aberration is shown?
- Two people are planning to have children together. Each person is heterozygous for the gene “G”. Using this letter, first list all the possible gametes that the two people can produce. Next, write all the possible genotypes and phenotypes for their offspring, using the correct genetic terminology (e.g., “genotype is homozygous dominant” “phenotype is dominant”). HINT: Use the gametes to construct a Punnett square and predict the possible offspring (you do not need to include the Punnett square in your answerWhich question can the student answer using the Punnett square? A What alleles did the father contribute? B What trait does the letter B represent? C How many mutations appear in the offspring? D How many female offspring are homozygous?Answer the following questions given the pedigree below. Please assume that no other mutations are occurring, complete penetrance, and that the individual marked with an asterisk (*) doesn’t carry the allele causing the affected phenotype. Q4) Assuming II-2 and II-3 want to have another child. what are all the possible genotypes, and what is the percentage that their child will be affected?
- Classical hemophilia is a sex-linked disease caused by a recessive gene on the X chromosome. (Hemophilia refers to diseases that cause delays in blood clotting.) If a woman who is acarrierof classical hemophilia has children with a normal male, give the ratios of the possible offspring with respect to classical hemophilia. Be sure to state both the genotypes and the phenotypes of each offspring. For genotypes, use X for a normal X chromosome, Xh for an X chromosome with the hemophilia gene, and Y for a normal Y chromosome. For phenotypes, if the offspring is female, be sure to state if homozygous normal, a carrier, or has the disease. If the offspring is a male, be sure to state if normal or has the disease.If I got an A from my father and a O from my mother for my genotype. How would my phenotype be expressed? What is my blood type? Explain your reasoning for both answers.A man who has type B blood (Genotype BO) and a woman who has type A blood (Genotype AO)are having children. What are the possible blood types for the children of the couple? Explainyour answer and the probabilities with a Punnett Square.