ΔG° is −32.7 kJ/mol of N2 for the reaction N2(g)+3H2(g) ⇌ 2NH3(g) ΔG° calculation was for the reaction under standard conditions—that is, with all gases present at a partial pressure of 1 atm and a temperature of 25°C. Calculate ΔG for the same reaction under the following nonstandard conditions: PN2 = 2.00 atm PH2 = 7.00 atm PNH3 = 0.021 atm T=100°C Does the reaction proceed forward or reverse to reach equilibrium?

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