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Q: Mass of water = 21.558 g Volume of water = 22.0 mL what is the density of water (g/mL
A: I have given the answer in the explanation section. Hope you will understand that.
Does the answer need 2 sig figs or 3?
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- Hexane (C6H14, density = 0.766 g/cm3), perfluoro-hexane (C6F14, density = 1.669 g/cm3), and water are immiscible liquids; that is, they do not dissolve in one another. You place 10 mL of each in a graduated cylinder, along with pieces of high-density polyethylene (HDPE, density = 0.97 g/cm3), polyvinyl chloride(PVC, density = 1.36 g/cm3), and Teflon (density = 2.3 g/cm3). None of these common plastics dissolves in these liquids. Describe what you expect to see.What is the smallest mass that we can measure on an analytical balance that has a tolerance of ±0.1 mg, if the relative error must be less than 0.1%?1. A graduated cylinder with a least count of ± 0.5 ml is used in a density experiment. The initial water level, before inserting the irregular shaped solid, is 30.0 ml. After inserting the solid, the water level is 34.5 ml. What is the probable error in the volume of the solid? What is the probable percent error in the volume of the solid?
- An electric current of 0.650 A flows for 1.0 second. Calculate the amount of electric, charge transported.. Be sure your answer has the correct unit symbol and 2 significant digits. 0 x10 ロ・ロ X μ = 5.:.Perform the calculations and determine the absolute and percent relative uncertainty. Express each answer with the correct number of significant figures. To avoid rounding errors, do not round your answers until the very end of your calculations. [9.8 (±0.3) — 2.31 (±0.01)] 8.5 (+0.6) = absolute uncertainty: + 0.76 Incorrect percent relative uncertainty: 0.88 + 86.36 Incorrect 9.2 (+0.4) × ([5.4 (±0.3) × 10−³] + [5.6 (±0.1) × 10-³]) = Incorrect %In a certain population, body weights are normally distributed with a mean of 152 pounds and a standard deviation of 26 pounds. How many people must be surveyed if we want to estimate the percentage who weigh more than 180 pounds? Assume that we want 96% confidence that the error is no more than 4 percentage points.
- 49) Calculate the length of a copper wire having a diameter of 0.200 cm and a mass of 15.620 g. The density of copper is 8.92 g/cm3. (Given: volume = 7 d2 L/4, where p = 3.14, d = diameter, and L = length) A) 1.80 x 10-4 cm B) 4.00 x 10-4 cm C) 1.75 cm %3D %3D %3D D) 5.50 × 10-2 cm E) 55.8 cmBoxes 1-4 box 1 answer choices: 0, 3, 1, 2, or 4. box 2 answer choices: 2, 1, 3, 0, or 4. box 3 answer choices: 10.7, 0.241. 0.482, 0.804, 5.36, 0.121, 3.21, or 1.61. Box 4 answer choices: L^2/mol^2•s, L^3/mol^3•s, L/mol•s, 1/s, or L^4/mol^4•sSuppose some measurements are made on two different homogeneous stones to find out if they are made of the same kind of rock. The mass and volume measurements are listed below. Are the two stones the same type of rock? Why or why not? Show all calculations. Mass Volume Calculations Stone 1 58.0 g 20.0 cm Stone 2 50.1 g 15.0 cm3 21/common/assets/pdfjs/1.0.0.30/web/viewer.ht...ndered-pdf&fullscreen=Dd21-fileviewer-rendered-pdf-dialog&height=746#0
- You have a stock solution certified by a manufacturer to contain 245.0 ± 0.4 µg SOź¯/mL. You would like to dilute it by a factor of 100 to obtain 2.450 µg/mL. Two possible methods of dilution are stated. For each method, calculate the resulting absolute uncertainty in concentration. Use the manufacturer's tolerances in the table for uncertainties. Glassware Tolerance 1-mL transfer pipet ±0.006 mL 10-mL transfer pipet +0.02 mL 100-mL volumetric flask +0.08 mL Method A: Dilute 10.00 mL up to 100 mL with a transfer pipet and volumetric flask. Then take 10.00 mL of the dilute solution and dilute it again to 100 mL. 0.0049 absolute uncertainty: ± ug/mL Incorrect Method B: Dilute 1.000 mL up to 100 mL with a transfer pipet and volumetric flask. 0.4 absolute uncertainty: ± ug/mL IncorrectAn electric current of 485.0 mA transports 760. uC of charge. Calculate the time this took. Be sure your answer has the correct unit symbol and 3 significant digits. x10 ロ・ロ X μ 3 5What is the error in the answer to the following? a) (22.10 ± 0.01) + (37.51 ± 0.02) = b) (30.88 ± 0.03) - (31.57 ± 0.06) = c) (5.88 ± 0.05) × (2.17 ± 0.01) =